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valentinak56 [21]
2 years ago
14

PLEASE HELP!! WILLING TO GIVE 20 POINTS!

Physics
1 answer:
sergey [27]2 years ago
3 0

The book is in motion and at the moment there is no one pushing it to the right. (Remember: a force is not needed to keep a moving object moving to the right.) The forces acting upon the book are shown below.

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What is inertia? (1 point)
snow_tiger [21]

The answer is C, an objects ability to not change its motion

Hope this helps!

4 0
2 years ago
Three forces are applied to an object, as shown in the diagram below. F1 = 30 N, F2 = 34 N, F3 = 20 N, d1 = 25 mm, d2 = 20 mm, d
lianna [129]
Torque of F1 = 30*0.025 = 0.75Nm anticlockwise
Torque of F2 = 34 * 0.020 = 0.68Nm clockwise
Horizontal component of F3:
cos 50 = x/20
x = 12.856 N

Torque of F3 horizontal component = 12.856 * 0.01 = 0.129Nm anticlockwise

0.129 + 0.75 - 0.68 = 0.199Nm anticlockwise

sorry I'm not sure is it correct
7 0
2 years ago
A 0.5 kg baseball is hit by a bat delivering an impulse of 180 kg x m/s. If the bat is in contact with the baseball for 0.4 seco
yan [13]

Answer:

450N

Explanation:

Impulse = mv    --->   180kgm/s = (0.5kg)v

v = 360 m/s

Acceleration = v/t    --->   a = (360 m/s)/(0.4s) = 900 m/s^2

Force = ma   --->   F = (0.5kg)(900 m/s^2) = 450N

Brainliest?

4 0
2 years ago
When an object with a negative charge is moved from point A to point B through an external electrical field, it gains electrical
Sergio039 [100]

Explanation:

As per the problem,

           \Delta U = (V_{B} - V_{A})(-q) > 0

When q > 0 then -q is a negative charge . Since, change in potential energy (\Delta U) increases.

or,     (V_{A} - V_{B})q > 0

or,      V_{A} > V_{B}

Therefore, both positive and negative charge will move from V_{A} to V_{B} and as V_{B} < V_{A} so both of them move through a negative potential difference.

Thus, we can conclude that the true statements are as follows.

  • The positively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).
  • The negatively charged object moves through a negative potential difference between A and B (that is, VB - VA < 0).      
4 0
2 years ago
. A 79 g sample of water at 21oC is heated until it becomes steam with a temperature of 143oC. Find the change in heat content o
mote1985 [20]

Answer:

40479.6 J

Explanation:

Applying,

q = cm(t₂-t₁).................... Equation 1

Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C

Constant: c = 4200 J/kg.°C

Substitute these values into equation 1

q = 4200(0.079)(143-21)

q = 331.8(122)

q = 40479.6 J

4 0
2 years ago
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