Answer:
2.475 mol of O2 formed.
Explanation:
Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.
x mole of O2 = 1.65 mol KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2
x mole of O2 formed = 2.475 mol of O2
Nitrogen — 78 percent.
Oxygen — 21 percent.
Argon — 0.93 percent.
Carbon dioxide — 0.04 percent.
Trace amounts of neon, helium, methane, krypton and hydrogen, as well as water vapor.
1.9264*10^23 is the answer
Answer:
0.00714 g
Explanation:
We know that the volume of one mole of a substance is 22400 cm^3
Thus;
1 mole of sulphur occupies 22400 cm^3
x moles of sulphur occupies 5.0 cm3
x = 5.0 cm3 * 1 mole/22400 cm^3
x = 2.23 * 10^-4 moles
Molar mass of sulphur = 32 g/mol
Mass of sulphur = 2.23 * 10^-4 moles * 32 g/mol
Mass of sulphur = 0.00714 g