HELp PLeaSE ‼️‼️URGENT

Chord AC intersects chord BD at point P in circle Z.

Alik [6]

In this question, we have to use the intersecting chord theorem, and the formula which is

$AP * CP = BP * DP$

In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .

Substituting the values in the formula, we will get

$12*6 = 5BP$

Dividing both sides by 5

$BP = \frac{72}{5} = 14.4 m$

4 0

3 years ago

Read 2 more answers

Suppose the function, g(x), is used to model the height ,y, of a soccer ball, x seconds after the ball is kicked up in the air.

andrey2020 [161]

the ball reaches its maximum height of 15 feet in 2.2 seconds

The ball starts on the ground and travels in a parabolic shape as it reaches a maximum height and then returns to the ground

The ball starts on the ground at 0 seconds so the ball starts at x=0 seconds

the ball reaches its maximum height of 15 feet in 2.2 seconds

So it takes 2.2 second to reach the maximum height

It will take another 2.2 seconds to reach the ground

The time the ball in the air is 2.2 + 2.2 = 4.4

The ball will reach the ground in 4.4 seconds

So the domain for g(x) is {0,4.4}

3 0

3 years ago

Help please. only answer if you know :(

Harrizon [31]

Answer:

x = 437.3 ft

Step-by-step explanation:

Right Triangles

In right triangles, where one of its internal angles measures 90°, the trigonometric ratios are satisfied.

We have completed the figure below with the missing internal angle A that measures A = 90° - 29° = 61° because the lines marked with an arrow are parallel.

Given the internal angle A, we can relate the unknown side of length x with the known side length of 500 ft, the hypotenuse of the triangle. We use the sine ratio:

$\displaystyle \sin 61^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}$

$\displaystyle \sin 61^\circ=\frac{x}{500}$

Solving for x:

$x = 500 \sin 61^\circ$

Calculating:

x = 437.3 ft

7 0

3 years ago

Four and one half times five and one half

zzz [600]

Where is the question

3 0

3 years ago

Read 2 more answers

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is 1 ton i.e. 2000 lbs.

Let x be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

4 years ago