The final temperature of the gas given the data from the question is 1527 °C
<h3>Data obtained from the question</h3>
- Initial volume (V₁) = V
- Initial temperature (T₁) = 27 °C = 27 + 273 = 300 K
- Final volume (V₂) = 6V
- Final temperature (T₂) =?
<h3>How to determine the new temperature </h3>
The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
V / 300 = 6V / T₂
Cross multiply
V × T₂ = 300 × 6V
Divide both side by V
T₂ = (300 × 6V) / V
T₂ = 1800 K
Subtract 273 from 1800 K to express in degree celsius
T₂ = 1800 – 273
T₂ = 1527 °C
Learn more about gas laws:
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Answer:
Acceleration of the object is 
.
Explanation:
It is given that, the position of the object is given by :
![r=[2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j](https://tex.z-dn.net/?f=r%3D%5B2%5C%20m%2B%285%5C%20m%2Fs%29t%5Di%2B%5B3%5C%20m-%282%5C%20m%2Fs%5E2%29t%5E2%5Dj)
Velocity of the object, 
Acceleration of the object is given by :
![a=\dfrac{d^2}{dt^2}([2\ m+(5\ m/s)t]i+[3\ m-(2\ m/s^2)t^2]j)](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bd%5E2%7D%7Bdt%5E2%7D%28%5B2%5C%20m%2B%285%5C%20m%2Fs%29t%5Di%2B%5B3%5C%20m-%282%5C%20m%2Fs%5E2%29t%5E2%5Dj%29)
Using the property of differentiation, we get :
So, the magnitude of the acceleration of the object at time t = 2.00 s is . Hence, this is the required solution.
Hello!
I believe its A. wrist flexors but im not exactly sure because it might be B. wrist extensors.
