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2 years ago

(0.50kg)(6.0mls)+(1.00kg)(-12.00mls)

Physics

1 answer:

Lana71 [14]2 years ago

6 0

Answer:

-9.0 × 10-6 m3 kg

Explanation:

I'm not sure if that's what you're looking for nor do I know how to explain it.

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with

Anna71 [15]

(D) The gravitational force between the astronaut and the asteroid.

Reason :

All the other forces given in the options, except (D), doesn't account for the motion of the astronaut. They are the forces that act between nucleons or atoms and neither of them accounts for an objects motion.

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3 years ago

if you have corona and you fart does it spread the corona sense its airborn?? should i start putting a mask over my anus to stop

Taya2010 [7]

Answer:

its soul for that context not sole also rip and i have no idea

Explanation:

4 0

3 years ago

Read 2 more answers

An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current

balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

Given;

emf of the battery, V = 16.0 V

current at 0.940 ms = 4.86 mA

after a long time, the current becomes 6.45 mA = maximum current

Part (a) The resistance R of the inductor

$R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms$

Part (b) the inductance L of the inductor

$\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}$

where;

L is the inductance

R is the resistance of the inductor

t is time

$L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H$

Therefore, the inductance is 1.67 H

5 0

3 years ago

13. A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V a

Lisa [10]

Answer:

The output power is 2 kW

Explanation:

It is given that,

Number of turns in primary coil, $N_p=250$

Number of turns in secondary coil, $N_s=500$

Voltage of primary coil, $V_p=200\ V$

Current drawn from secondary coil, $I_s=5\ A$

We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :

$\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}$

$\dfrac{250}{500}=\dfrac{200}{V_s}$

$V_s=400\ V$

So, the power output is :

$P_s=V_s\times I_s$

$P_s=400\ V\times 5\ A$

$P_s=2000\ watts$

$P_s=2\ kW$

So, the output power is 2 kW. Hence, this is the required solution.

8 0

3 years ago

Which statement is true according to Newton's first law of motion?

lys-0071 [83]

An object in motion tends to stay in motion an oject at rest stays at rest.

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3 years ago