Answer:
40 rubber bands are needed
5 rubber bands will be left from 5 bags of of rubber band
Step-by-step explanation:
Each student will need five rubber bands.
There are eight students
Total rubber bands needed = rubber bands per student × number of students
= 5 × 8
= 40
Total rubber bands needed = 40
Rubber bands come in bags of nine.
Number of bags needed = Total rubber bands needed / number of rubber bands in each bag
= 40 / 9
= 4.44 bags
It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5
5 rubber bands bags will be bought which = 5 × 9
= 45 rubber bands
Only 40 rubber bands are needed
Left over rubber bands = 45 - 40
= 5 rubber bands
Step-by-step explanation:
Applying rules of exponents to solve the given problems;
4^3 x 4^5 =
5^8 ÷ 5^-2 =
(6^3 ) ^ 4 =
For these problems, the applicable rules of exponents are;
aᵇ x aⁿ = aᵇ⁺ⁿ
aᵇ ÷ aⁿ = aᵇ⁻ⁿ
(aᵇ)ˣ = aᵇˣ
For the first problem; 4³ x 4⁵
aᵇ x aⁿ = aᵇ⁺ⁿ
4³ x 4⁵ = 4³⁺⁵ = 4⁸
Second problem: aᵇ ÷ aⁿ = aᵇ⁻ⁿ
5⁸ ÷ 5⁻² = 5⁸⁻⁽⁻²⁾ = 5⁸⁺² = 5¹⁰
Third problem; (aᵇ)ˣ = aᵇˣ
(6³)⁴ = 6³ˣ⁴ = 6¹²
Answer:
its 2,4,6 - b,d,f
Step-by-step explanation:
The three points form a straight line.
The graph does not pass through the origin.
The graph does not a show a proportional relationship.
Answer:
The equations that are equal to 15-8y=-11 are...
- Number 1
- Number 4
We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.
Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1
As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40
Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
we see that :
x → 1 - 1/x → 1/(1-x) →xso that:
g(g(g(x))) = x.
Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)
As,
h(x) = (1+x)/(1−x)which satisfies
h(h(h(h(x)))) = xNow, mapping x to h(x) corresponds to rotating the circle by ninety degrees.