The standard form of a line is in the form
A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:
Subtract 3y from both sides:
Which of course is equivalent to
Which is the standard form, given the coefficients A=1, B=-3, C=6.
(X^2+8x)-(x-8)=0
x(x+8)-1(x+8)=0
(X-1)(x+8)=0
X= 1
X= -8
Answer:
CBA is a secant.
Step-by-step explanation:
Answer:
x = 21/8
Step-by-step explanation:
Step 1: Write equation
x - 11 = 3 - 7(x - 1)
Step 2: Solve for <em>x</em>
<u>Distribute -7:</u> x - 11 = 3 - 7x + 7
<u>Combine like terms:</u> x - 11 = 10 - 7x
<u>Add 7x on both sides:</u> 8x - 11 = 10
<u>Add 11 on both sides:</u> 8x = 21
<u>Divide both sides by 8:</u> x = 21/8
I think it's true but I'm not sure about that
