Molarity = number of moles / volume in liters solution
Answer (4)
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Answer:
4.35 atm
Explanation:
According to the information given;
- Initial volume of the gas, V₁ is 2.50 L
- Initial pressure of the gas is standard pressure P₁, normally 1 atm
- New volume of the gas, V₂ is 575 mL
We are required to determine the new pressure of the gas, P₂ ;
To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.
According to Boyle's law;
P₁V₁ = P₂V₂
Therefore, to determine the new pressure, P₂, we rearrange the formula;
New pressure, P₂ = P₁V₁ ÷ V₂
Thus;
P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L
= 4.3478 atm
= 4.35 atm
Therefore, the new pressure of the gas is 4.35 atm
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L
Given:
<span>BaO2(s) + 2 HCl(aq) => H2O2(aq) + BaCl2(aq)
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Mass of barium peroxide = 1.49 g Volume of HCl solution = 25.1 mLConcentration of HCl solution = 0.0279 g HCl per mL
Solution: To determine the amount of hydrogen peroxide that would be produced, we use need to determine which is the limiting reactant and use the initial amount of this reactant for the calculations.
0.0279 g HCl / mL ( 25.1 mL ) ( 1 mol HCl / 36.46 g HCl) ( 1 mol BaO2 / 2 mol HCl ) = 0.0096 mol BaO2 needed
1.49 g BaO2 ( 1 mol / 169.3 g BaO2 ) ( 2 mol HCl / 1 mol BaO2 ) = 0.0176 mol HCl needed
Therefore, the limiting reactant would be barium peroxide since it is consumed completely first in the reaction.
1.49 g BaO2 ( 1 mol BaO2 / 169.3 g BaO2 ) ( 1 mol H2O2 / 1 mol BaO2 ) ( 34.02 g H2O2 / 1 mol H2O2 ) = 0.299 g H2O2
