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3 years ago

Which family of elements can be found in the area marked B

Chemistry

1 answer:

postnew [5]3 years ago

3 0

Answer:

A) Alkaline Earth Metals

Explanation:

Area Marked A would be Alkali Metals

Area Marked B would be Alkaline Earth Metals

Area Marked C would be Transition Metals

Area marked H would be Halogens

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Baker’s Yeast is usually added to dough in baking products. It contains enzymes (catalysts) that are necessary for the rising do

STatiana [176]

Answer:

When I first began making bread, the science involved was always in the back of my mind. I had an idea of what occurred—my diagram for the chemical reactions

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2 years ago

Which is bigger in width mm,cm,m,km

Kay [80]

Km is the biggest measure in width (even if there are bigger measures like Mm, Gm, Tm).

1 Km = 1000 m, 100000 cm and 1000000 mm

4 0

3 years ago

Read 2 more answers

A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica

Sladkaya [172]

Answer: The empirical formula for the given compound is $CH_5N$

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = $\frac{3.23}{3.23}=1$

For Hydrogen = $\frac{16.2}{3.23}=5.01\approx 5$

For Oxygen = $\frac{3.24}{3.23}=1.00\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is $C_1H_5N_1=CH_5N$

3 0

3 years ago

Rutherfordium has atomic number of 84 how many protons and electrons does it have

valentina_108 [34]

84 protons and 84 electrons.

5 0

3 years ago

Calculate the molarity and normality of 5.7 g of Ca(OH)2 in 450 mL of solution.

Kisachek [45]

The molarity and normality of 5.7 g of Ca(OH)2 in 450ml 0f solution is calculated as follows

molarity = moles/volume in liters
moles =mass/molar mass
= 5.7g/74g/mol = 0.077moles
molarity = 0.077/450 x1000= 0.17M

Normality = equivalent point x molarity
equivalent point of Ca(OH)2 is 2 since it has two Hydrogen atom

normality is therefore = 0.17 x2 = 0.34 N

7 0

3 years ago