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irga5000 [103]
3 years ago
11

The half-life of hydrogen-3 (tritium) is approximately 12 years. In how many years will half of a 20-gram sample decay by beta r

adiation to helium-3?
6
12
10
20
Chemistry
2 answers:
Gelneren [198K]3 years ago
6 0

Answer:

12 years

Explanation:

anyanavicka [17]3 years ago
4 0
<h3>Answer:</h3>

12 years

<h3>Explanation:</h3>

We are given;

Half life of hydrogen-3 is 12 years

Initial mass of Hydrogen-3 is 20 grams

Final mass will be 10 g because we are told half of the sample will decay.

To find the time taken for the decay we need to know what half life is;

  • Half life is the time taken for a radioactive isotope to decay to half its original amount.
  • Using the formula;

Remaining mass = Original mass × 0.5^n

n = number of half lives

therefore;

10 g = 20 g × 0.5^n

0.5 = 0.5^n

n = log 0.5 ÷ log 0.5

  = 1

But, 1 half life is 12 years

Therefore, the time taken is 12 years

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An atom of an element has 54 protons. Some of the elements atoms have 77 neutrons, while other atoms have 79 neutrons. What are
Alja [10]

Answer:

The atomic numbers of both are 54 while the mass numbers are 131 and 133 respectively.

Explanation:

- The number of protons = Atomic number. So, if the atom has 54 protons and it remained unchanged, then the two types of atoms of this element both have atomic numbers of 54.

- On the other hand, mass number is the sum of protons and neutrons

So, if type 1 has protons = 54 and neutrons = 77: mass number = 54 + 77 = 131

if Type 2 has protons = 54 and neutrons = 79: mass number = 54 + 77 = 133

(Since the possibility of atoms of the same element to have different mass numbers but the same atomic number is called isotopy). The two types of atoms with mass numbers 131 and 133 described are isotopes.

7 0
3 years ago
What is the ratio of sodium ions to bromide ions in neutral sodium bromide?
frosja888 [35]
The ratio of <span>sodium ions to bromide ions in neutral sodium bromide would be 1 is to 1. The molecular formula of sodium bromide would be NaBr where in every ion of Na there is one corresponding ion of bromide present. Hope this helps. Have a nice day.</span>
4 0
4 years ago
Read 2 more answers
The reaction of 9.50 g of carbon with Excess O2 Yield 12.8 of CO2. What is the percent yield of this reaction?
Anna [14]

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

5 0
3 years ago
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates
LuckyWell [14K]
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
8 0
4 years ago
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EastWind [94]

Answer:

Cl2.

Explanation:

? + 2NaBr → 2NaC1l+ Br2

Note that the element Cl (chlorine) is missing from the left side.

The answer is Cl2  (to balance the equation it requires 2 Cl's).

5 0
3 years ago
Read 2 more answers
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