All categories

2 years ago

Which of the balls will exert the greatest force on object A?Why?

Physics

1 answer:

iren [92.7K]2 years ago

7 0

F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

You might be interested in

Why is electric magnet a temporary magnet

PtichkaEL [24]

The electric magnet (Electromagnetic) is temporary because you can turn it on and off. When it's power source is gone, the magnet becomes useless. Usually it's power source is a battery, but it could be solar with a switch. Hope this helps. Please give me brainliest is this helps you.

6 0

3 years ago

Consider the 4-step staircase. All steps provide an equal elevation gain. The potential energy (PE) on the top step is 16.0 J. D

iragen [17]

Potential energy, PE = 0, 4, 8 and 12 at level 1, 2, 3, 4 respectively.

At Level 5, potential energy = 0 and Kinetic energy = 24 J.

<h3>Potential and Kinetic energy</h3>

Potential energy is the energy a body has by virtue of its position or state.

The formula for calculating the potentials energy of a body is given as:

Potential energy, PE = mgh

where m = mass of the body

g = acceleration due to gravity

h = height

Kinetic energy is the the energy a body has by virtue of its motion.

The formula for calculating kinetic energy of a body is given as:

Kinetic energy, KE = 1/2mv^2

The sum of the kinetic energy and potential energy of a body is constant.

Assume the ball has unit mass; m = 1

g = 10 m/s^2

At the top, total energy of the body = 16 + 8 = 24J

Calculating the gain in height for each step:

At Level 4, PE = 16 J

mgh = 16 J

1 × 10 × h = 16

h = 16/10

h = 1.6 m

Since there are four steps, each step will have a height increase = 1.6/4 = 0.4

At Level 1, h = 0

PE = 0 × 1 × 10

PE = 0 J

At Level 2, h = 0.4 m

PE = 0.4 × 1 × 10

PE = 4 J

At Level 3, h = 0.8 m

PE = 0.8 × 1 × 10

PE = 8 J

At Level 5, PE + KE = 24 J

Since PE = 0

KE = 24

Therefore, potential energy, PE = 0, 4, 8 and 12 at level 1, 2, 3, 4 respectively.

At Level 5, potential energy = 0 and Kinetic energy = 24 J.

Learn more about potential energy and Kinetic energy at: brainly.com/question/14427111

6 0

3 years ago

In order to generate electricity, nuclear power plants take advantage of this part of the electromagnetic spectrum. gamma rays r

Nat2105 [25]

Well, it is not ultraviolet rays and I highly doubt it is visible light. I would say gamma rays. Hope this helps! :)

6 0

3 years ago

Read 2 more answers

ASAP is the object of soccer ??????

n200080 [17]

Soccer is a sport that has offense, people in the middle, and defense. The goal to playing soccer is to get past the defenders by using teamwork and score more goals than the other team to win.

6 0

3 years ago

A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in

Slav-nsk [51]

<h3>Answer:</h3>

$\displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}$

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: $\overline{P} = m \overline{v}$

P is momentum (in kg · m/s)
m is mass (in kg)
v is velocity (in m/s)

Law of Conservation of Momentum: $\sum \overline{P_i} = \sum \overline{P_f}$

States that the sum of initial momentum must equal the sum of final momentum

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[LCM] $\sum \overline{P_i} = \sum \overline{P_f}$ → $m_{1} \overline{v_{1i}} + m_{2} \overline{v_{2i}} = (m_{1} + m_{2}) \overline{v_{f}}$

m₁ (ball) = 7.00 kg

m₂ (man) = 75.0 kg

$\overline{v_{1i}} = ?$

$\overline{v_{2i}} = 0 \ \frac{m}{s}$ (man starts from rest)

$\overline{v_{f}} = 3.00 \ \frac{m}{s}$ (the ball and the man are one mass because the man catches and <em>keeps</em> the ball)

We know no energy is lost because it is a frictionless surface. The collision should be perfectly elastic.

<u>Step 2: Solve</u>

Substitute in variables [Law of Conservation of Momentum]: $\displaystyle (7.00 \ kg) \overline{v_{1i}} + (75.0 \ kg)(0 \ \frac{m}{s}) = (7.00 \ kg + 75.0 \ kg)(3.00 \ \frac{m}{s})$
Multiply: $\displaystyle (7.00 \ kg) \overline{v_{1i}} + 0 = 246 \ kg \cdot \frac{m}{s}$
Simplify: $\displaystyle (7.00 \ kg) \overline{v_{1i}} = 246 \ kg \cdot \frac{m}{s}$
[Division Property of Equality] Isolate unknown: $\displaystyle \overline{v_{1i}} = \frac{246}{7} \ \frac{m}{s}$
[Evaluate] Divide: $\displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}$

The initial speed of the ball should be approximately 35.14 m/s.

8 0

3 years ago

Read 2 more answers