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garri49 [273]
3 years ago
9

A point charge 20.0 nC is located at the center of a cube whose sides are of length 10.0 cm. If there is no other charges in thi

s system, what is the electric flux through one face of the cube?
Physics
1 answer:
stealth61 [152]3 years ago
3 0

Answer:

ϕ_Net = 2258.87 Nm²/C

Explanation:

We are given;

Charge; q = 20 nC = 20 × 10^(-9) C

Length of each side; L = 10 cm = 0.1 m

The net electric flux through one face of the cube is given by the formula;

ϕ_Net = q/ε_o

Where ε_o is a constant known as vacuum of Permittivity and has a value of 8.854 × 10^(−12) C²/N.m²

Thus;

ϕ_Net = (20 × 10^(-9))/(8.854 × 10^(−12))

ϕ_Net = 2258.87 Nm²/C

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A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms.
victus00 [196]

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ e^{-\lambda t}

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ e^{-\lambda_1 t}

For B

N(B) = N(B)₀ e^{-\lambda_2 t}

N(A) = N(B) , for t = 2 h

N(A)₀ e^{-\lambda_1 t} = N(B)₀ e^{-\lambda_2 t}

N(A)₀ e^{-\lambda_1 t} = 5 x N₀(A)  e^{-\lambda_2 t}

e^{-\lambda_1 t} = 5  e^{-\lambda_2 t}

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

e^{\lambda_2 t} = 5  e^{\lambda_1 t}

Putting t = 2 h , λ₁ = .9 h⁻¹

e^{\lambda_2\times  2} = 5  e^{.9\times  2}

e^{\lambda_2\times  2} = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

6 0
3 years ago
Please just check answers ! will give medal for support !. What do you call a wave that is made up of electric and magnetic fiel
tangare [24]
<span>electromagnetic wave

</span>
<span>as both a wave and a particle

</span>
sun

6 0
4 years ago
Read 2 more answers
SOME HELP PLEASE
ddd [48]

Matter that is composed of a single element and has all the same physical properties would be a substance

Matter that is made of molecules of all the same type are elements

Two atoms chemically bonded together is a compound

A substance made of two or more types of atoms that are not chemically bonded is a mixture

the last one is correct answer

4 0
4 years ago
Read 2 more answers
In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.
garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...

Find the equivalent resistance of the right branch of the circuit:

R_{eq}  = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms

\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

6 0
3 years ago
If you slosh the water back and forth in a bathtub at the correct frequency, the water rises first at one end and then at the ot
notka56 [123]

Answer:

Velocity(v) = frequency(f) × wavelength

f = 0.3165

Wavelength = 2×length(L)

L = 157cm

Convert the length in centimetres to metre = 1.57m

v = 2×1.57 × 0.3165

v = 0.99m/s

Approx. 1m/s

Explanation:

The velocity of a wave is the product of its frequency and it's wavelength. The frequency is already known. The wavelength is the distance between two successive wave crests which is formed by sloshing water back and forth in the bath tub. Sloshing water to one end of the tub will produce a wave crest first at that end then the other completing a cycle. The wavelength will be twice the length of the bath tub as it is the distance that both crests are formed.

Wave crest is the highest point of a wave, and in this case is where the water rises to a high point in the bath tub

7 0
3 years ago
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