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nirvana33 [79]
3 years ago
14

PLSSS HELP IF YOU KNOW THISS

Chemistry
2 answers:
mixas84 [53]3 years ago
8 0

Answer:

C

Explanation:

Introspection is the examination of one's own conscious thoughts and feelings.

Introspection is closely related to human self-reflection and self-discovery and is contrasted with external observation.

Cerrena [4.2K]3 years ago
5 0

Answer:Its gonna be C i hope if not u can yell at me

Explanation: Introspection is the examination of one's own conscious thoughts and feelings. In psychology, the process of introspection relies on the observation of one's mental state, while in a spiritual context it may refer to the examination of one's soul.  

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A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0
miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

Q_{metal} - Q_{water} = 0

Q_{metal} = Q_{water}

Where:

Q_{water} - Heat received by water, measured in joules.

Q_{metal} - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})

The specific heat of the metal is cleared within equation above:

c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}

If we know that m_{water} = 0.237\,kg, m_{metal} = 0.244\,kg, c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}, T_{w,o} = 10\,^{\circ}C, T_{m,o} = 100.10\,^{\circ}C and T = 15.30\,^{\circ}C, the specific heat of molybdenum is:

c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}

c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

5 0
3 years ago
Formular for solubility​
Komok [63]

Answer:

= konstanta produk kelarutan

= kation dalam larutan berair

= anion dalam larutan berair

= konsentrasi relatif a dan b

DARI WEB

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g . Solubility of NaNO3=21.9g or NaNO3 x 100 g/ 25 g =87.6. Calculate the molar mass of the dissolved compound as the sum of mass of all atoms in the molecule.

6 0
3 years ago
Read 2 more answers
Atoms- 1 2 3 4
liq [111]

Answer:

The ones with 8 protons

Explanation:

Since there are two of them with 8 protons, we can assume they are the same element. The first 8 proton element has 10 neutrons while the second has 11. This makes them isotopes of one another

7 0
3 years ago
By using the titration technique, what can be determined about a given substance?
gtnhenbr [62]
It is strong. it is really strong


3 0
3 years ago
Read 2 more answers
We can also use the activity series to predict reactions between a metal and an acid. what are the products of the reaction fe(s
andrew11 [14]

Answer;

FeSO4 (aq) + H2 (g)

Explanation;

The reaction between iron and dilute sulfuric acid gives a salt and hydrogen gas. (iron (ii) sulfate and hydrogen gas).

The equation for the reaction is;

Fe(s) + H2SO4 (aq) = FeSO4(aq) +H2(g)

8 0
4 years ago
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