Pls help ill mark as brainliest :)

Why it is necessary for plants to have chloroplasts?<br><br> In your own words, please

algol13

Chloroplasts is an important part in the process of photosynthesis in some organisms. The chloroplast absorbs the energy in sunlight and uses it to produce sugars.

7 0

3 years ago

If 2.06 mL of seawater contains about 0.446 moles of gold, how many atoms of gold are in that volume of seawater?

Alborosie

Answer:

2.69 x 10²³ atoms

Explanation:

Given parameters:

Volume of sea water = 2.06mL

number of moles of gold = 0.446moles

unknown:

Number of atoms in the sea water

Solution:

The mole is a convenient unit of measuring quantities of particles. In a mole we have 6.02 x 10²³particles.

The mole can be defined as the amount of a substance contained in Avogadro's number of particles which is 6.02 x 10²³particles.

Here, the particles we want to determine is the number of atoms:

Number of atoms is given as:

Number of gold atoms = number of moles of gold x 6.02 x 10²³

Number of gold atoms = 0.446 x 6.02 x 10²³ = 2.69 x 10²³ atoms

5 0

4 years ago

What is the balanced chemical reaction when Aluminium reacts with NaOH to produce NaAlO2 and H2 gas?

8090 [49]

Answer:

2NaOH + 2Al +2H2O = 2NaAlO2 +3H

Explanation:

Aluminum is an amphoteric element it reacts with both bases and acids to form a salt and hydrogen gas.The reaction is highly exothermic.

5 0

3 years ago

The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago

Question 2 (5 points)

blagie [28]

The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

Option D

<h3>Chemical Reactions</h3>

Generally,the experiment shows that glass B temperature is higher than glass temperature A and this is given that observation that the solute dissolves faster in glass B than glass A.

Therefore,The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

For more information on Temperature

brainly.com/question/13439286

5 0

2 years ago