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3 years ago

Pls help ill mark as brainliest :)

Chemistry

1 answer:

Alina [70]3 years ago

4 0

Answer:

I think its a double reaction

Explanation:

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The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the

IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

Explanation :

The expression for first order reaction is:

$[C_t]=[C_o]e^{-kt}$

where,

$[C_t]$ = concentration at time 't' (final) = ?

$[C_o]$ = concentration at time '0' (initial) = 0.100 M

k = rate constant = $5.40\times 10^{-3}s^{-1}$

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

$[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}$

$[C_t]=4.05\times 10^{-4}M$

Thus, the concentration after 17.0 minutes will be, $4.05\times 10^{-4}M$

4 0

2 years ago

A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field

maksim [4K]

Answer:

the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

The electric field, E at a point on the central axis of a charged disk is given by E = σ/ε₀( $1 - \frac{z}{\sqrt{z^{2} + R^{2} } }$ )

Substituting the values into the equation, it becomes

E = σ/ε₀( $1 - \frac{z}{\sqrt{z^{2} + R^{2} } }$ ) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²( $1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }$ ) = 7.12 × 10⁵( $1 - \frac{0.12}{0.1216}$ ) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

Therefore, the electric field at Z = 12 cm is E = 9.68 × 10³ N/C = 9.68 kN/C

7 0

3 years ago

if the Celsius temperature of a gas at constant pressure is increased from 10 Celsius to 20 Celsius the volume is

svet-max [94.6K]

Answer:

The volume is increased.

Explanation:

According to Charles' Law, " at constant pressure the volume and temperature of the gas are directly proportional to each other". Mathematically this law is presented as;

V₁ / T₁ = V₂ / T₂ -----(1)

In statement the data given is,

T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C

T₂ = 20 °C = 293.15 K

So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,

V₁ = 100 L

V₂ = Unknown

Now, we will arrange equation 1 for V₂ as,

V₂ = V₁ × T₂ / T₁

Putting values,

V₂ = 100 L × 293.15 K / 283.15 K

V₂ = 103.52 L

Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.

3 0

2 years ago

Help!! What is the concentration of an unknown with an absorbance of 0.4 using the plot?

sveta [45]

Answer:3,4,1,2

Explanation:

hope this helped

6 0

2 years ago

How many electrons can occupy the 4p sublevel of a neutral atom of bromine

VMariaS [17]

Answer:

Explanation

every p sublevel holds up to 6 electrons

so the 4p sublevel must hold up to 6 electonsr

4 0

2 years ago