Answer:
2Mg(s) +O₂(g) → 2MgO(s)
Explanation:
Mg(s) +O₂(g) → MgO(s)
When a chemical equation is balanced, the number of atoms of each element is equal on both sides of the arrow. We usually balance O and H last.
In this case, the number of Mg atoms is equal on both sides. Thus, let's move on to balance the O atoms. On the left side, there are 2 O atoms, while there is only 1 O atom on the left side. Thus, write a '2' in front of MgO.
Mg(s) +O₂(g) → 2MgO(s)
Now, the number of Mg atoms is not equal. Write a '2' in front of Mg to balance it.
2Mg(s) +O₂(g) → 2MgO(s)
The equation is now balanced with 2 Mg atoms and 2 O atoms on each side.
Answer:
YASSSSSSS
Explanation:
i think the answer is true
Answer:
449 mL
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 450 mL
V₂ = ?
P₁ = 101 kPa
P₂ = 104 kPa
T₁ = 17 ºC
T₂ = 25 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (17 + 273.15) K = 290.15 K
T₂ = (25 + 273.15) K = 298.15 K
Using above equation as:
Solving for V₂ , we get:
V₂ = 449 mL
