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Bogdan [553]
2 years ago
15

If an object is accelerating at a rate of 8 m/s^2 what is the mass of the box. See attached

Physics
1 answer:
Orlov [11]2 years ago
6 0

Answer:

50 kg

Explanation:

fnet=ma

600-200=m8

divide both side by 8 to make m the subject of the formula Thus m=50kg

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1. A ball initially rolling at 10m/s comes to a stop in 25 seconds. Assuming the ball has
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3 years ago
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Zolol [24]

Answer:

1. v = 6.67 m/s

2. d = 9.54 m

Explanation:

1. To find the horizontal velocity of the rock we need to use the following equation:

d = v*t \rightarrow v = \frac{d}{t}    

<u>Where</u>:

d: is the distance traveled by the rock

t: is the time

The time can be calculated as follows:

t = \sqrt{\frac{2d}{g}}

<u>Where:</u>

g: is gravity = 9.8 m/s²

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Now, the horizontal velocity of the rock is:

v = \frac{d}{t} = \frac{8 m}{1.20 s} = 6.67 m/s      

Hence, the initial velocity required to barely reach the edge of the shell below you is 6.67 m/s.          

2. To calculate the distance at which the projectile will land, first, we need to find the time:

t = \sqrt{\frac{2d}{g}} = \sqrt{\frac{2*(7 m + 3 m)}{9.8 m/s^{2}}} = 1.43 s

So, the distance is:

d = v*t = 6.67 m/s*1.43 s = 9.54 m    

Therefore, the projectile will land at 9.54 m of the second cliff.

I hope it helps you!        

7 0
3 years ago
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