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3 years ago

Physics. How to solve this?

Physics

1 answer:

attashe74 [19]3 years ago

4 0

You can't.

Work = (force) x (distance) .

You can squeeze distance out of the speed, but there's no way to determine the FORCE being used.

If there's no friction and the car is traveling in a straight line, then NO force is needed to keep it going. It just keeps going. (Newton's 1st law of motion.)

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A flywheel with radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.400 rad/s2.For a po

oksian1 [2.3K]

Answer:

$0.12\ m/s^2$

Explanation:

Given that,

The radius of a flywheel, r = 0.3 m

Angular acceleration of a flywheel, $\alpha =0.4\ rad/s^2$

We need to find the magnitude of the tangential acceleration after 2.00 s of acceleration.

The relation between the tangential and angular acceleration is given by :

$a_t=r\alpha \\\\a_t=0.3\times 0.4\\\\a_t=0.12\ m/s^2$

So, the required magnitude of tangential acceleration is $0.12\ m/s^2$ .

6 0

3 years ago

Tamika looks out a clear glass window on a sunny day. Which best explains why Tamika can see outside when she looks at the windo

zimovet [89]

I think the answer is C. it seems the most logical

5 0

3 years ago

Read 2 more answers

State Archimedes' principle

OlgaM077 [116]

Explanation:

Archimedes' principle states that the upward buoyant force which is exerted on body when immersed whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.

Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

6 0

3 years ago

A 10 kg ball has a momentum of 40 kg.m/s.what is the ball's speed?

iren [92.7K]

M = 10kg
P = 40 kg.m/s
V= 4m/s

Formula v = p/m

V= p/m
=4okg.m/s / 10kg
=4m/s

7 0

3 years ago

A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .

zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

$F=m\times a$

$F=m\times (\dfrac{v-u}{t})$

$F=0.003\times (\dfrac{30}{0.06})$

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

6 0

3 years ago