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3 years ago

According to Newton's First Law of Motion _____.

Physics

2 answers:

Contact [7]3 years ago

8 0

Answer:

every action has an equal and opposite reaction

laila [671]3 years ago

5 0

Answer:

inertia

Explanation:

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A biker pedals hard to ride his bike to the top of a 44 m hill. He decides to let his bike coast down the hill, and is having so

Vanyuwa [196]

The biker's speed at the top of the second hill is 25.8 m/s

Explanation:

The problem can be solve by applying the law of conservation of energy. In absence of frictional forces, the total mechanical energy of the bike (the sum of potential energy + kinetic energy) must be conserved. So we can write:

$U_i +K_i = U_f + K_f$

where

$U_i$ is the initial potential energy at the top of the first hill

$K_i$ is the initial kinetic energy at the top of the first hill

$U_f$ is the final potential energy at the top of the second hill

$K_f$ is the final kinetic energy at the top of the second hill

We can rewrite the equation as:

$mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2$

where:

m is the mass of the bike

$g=9.8 m/s^2$ is the acceleration of gravity

$h_i = 44 m$ is the height of the first hill

u = 0 m/s is the speed at the top of the first hill

$h_f = 10 m$ is the height of the second hill

v is the speed at the top of the second hill

And solving for v, we find:

$mgh_i = mgh_f + \frac{1}{2}mv^2\\v^2=\sqrt{2g(h_i-h_f)}=\sqrt{2(9.8)(44-10)}=25.8 m/s$

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0

3 years ago

A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an

maksim [4K]

Answer:

The value is $\alpha = 0.002 Np/m$

Explanation:

From the question we are told that

The first amplitude of the wave is $E_{max}1 = 98.02 \ V/m$

The first depth is $D_1 = 10 \ m$

The second amplitude is $E_{max}2 = 81.87 \ (V/m)$

The second depth is $D_2 = 100 \ m$

Generally from the spatial wave equation we have

$v(x) = Ae^{-\alpha d}cos(\beta x + \phi_o)$

=> $\frac{v(x)}{v(x)} =\frac{ Ae^{-\alpha d}cos(\beta x + \phi_o)}{ Ae^{-\alpha d}cos(\beta x + \phi_o)}$

So considering the ratio of the equation for the two depth

$\frac{A}{A_S} = \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}$

=> $\frac{98.02}{81.87} = \frac{e^{-10 \alpha }}{e^{-100 \alpha }}$

=> $\alpha = \frac{0.18}{90}$

=> $\alpha = 0.002 Np/m$

4 0

3 years ago

Which type of galaxy is too small for gravity to form it into an easily describable shape?

oksano4ka [1.4K]

If you think about it, irregular galaxies dont really have a describable shape, as you can tell by the name. So B.

6 0

3 years ago

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two children having a disagreement pull on a 50N sled in opposite directions. one pulls with a force of 300N east, the other wit

prohojiy [21]

<span>Since forces are vector quantities, we must indicate direction using positive and negative values. East will be assigned positive and west will be negative. Friction will act as a negative force since it impedes action. To calculate the net force we sum the vector quantities, as follows. Net force equals 50n which is derived by the following calculation: 300n-220n-30n.</span>

7 0

3 years ago

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A red laser with a wavelength of 670 nm and a blue laser with a wavelength of 450 nm emit laser beams with the same light power.

tatyana61 [14]

E=hf C=wavelength*F

E=hC/wavelength

E=(6.626*10^-34)*(3.00*10^8)/670*10^-9

E=(6.626*10^-34)*(3.00*10^8)/450*10^-9

6 0

3 years ago