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3 years ago

A student walks 10 m North, 6 m South, 7 m West and 4 m East. Find the student's distance AND displacement

Physics

1 answer:

BlackZzzverrR [31]3 years ago

5 0

Answer: Distance: 27m Displacement: 7m

Explanation: Distance is total, Displacement is from the start.

Hope this helped!

Mark Brainliest if you feel like it!

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A force of gravity pulls downward on a book on a table. What force prevents the book from accelerating downward?

Nadusha1986 [10]

Answer: The Normal Force

Explanation:

According to Third Newton's Law, also konwn as The principle of action and reaction :

<em>"If a body A exerts an action on another body B, it performs on A another action that is the same and in the opposite direction."</em>

In this case this is what happens with the book on a table, gravity force pulls it downward, but the Normal Force (perpendicular to the surface of the table) acts in the opposite direction with the same magnitude, preventing the book from accelerating downward.

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3 years ago

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Remember to identify all your data, write the equation, and show your work.

Paraphin [41]

Answer:

I believe it's 8.09 seconds, but I'm rusty on my physics.

Explanation:

The equation for solving the time it takes for an object to fall is $\sqrt{2d/g}$

So multiply the distance times 2, and you get 642 meters. Then you divide by gravities acceleration constant, 9.8, and you get 65.51. Finally, $\sqrt{65.51}$ , and you get 8.09 seconds.

I pulled the equation off of wikipedia and I'm unsure if it's the correct one, so hopefully this is correct. :/

6 0

2 years ago

lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of

bonufazy [111]

Answer:

The intensity of laser 2 is 4 times of the intensity of laser 1.

Explanation:

The intensity in terms of electric field is given by :

$U=\dfrac{1}{2}\epsilon_o E^2$

E is electric field

It means, $U\propto E^2$

In this problem, lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2.

Let E is electric field in the beam of laser 1 and E' is the electric field in the beam of laser 2. So,

$\dfrac{U}{U'}=(\dfrac{E}{E'})^2$

We have,

E'=2E

So,

$\dfrac{U}{U'}=\dfrac{E^2}{(2E)^2}\\\\\dfrac{U}{U'}=\dfrac{E^2}{4E^2}\\\\\dfrac{U}{U'}=\dfrac{1}{4}\\\\U'=4\times U$

So, the intensity of laser 2 is 4 times of the intensity of laser 1.

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3 years ago

The light bulb in your room is not very bright. You want to use a concave mirror to direct its illumination into a tight, parall

ehidna [41]

A point source is to be used with a concave mirror to produce a beam of parallel light. The source should be placed midway between the center of curvature and the mirror. To solve this question you have to draw a ray diagram. Apply the mirror equation to determine the image distance and finally make sure that the first two steps are consistent with each other.

<span>I hope this helps, Regards.</span>

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3 years ago

Anna learned that every magnet has a north and a south end called poles. One day, while she is playing with magnets she notices

My name is Ann [436]

Just from that one observation, choice-B
would be a reasonable conclusion.

4 0

3 years ago

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