It sounds like <em>R</em> is the region (in polar coordinates)
<em>R</em> = {(<em>r</em>, <em>θ</em>) : 2 ≤ <em>r</em> ≤ 3 and 0 ≤ <em>θ</em> ≤ <em>π</em>/2}
Then the integral is

<span>Yes it is true that a continuous function that is never zero on an interval never changes sign on that interval. This is because of ever important Intermediate Value Theorem.</span>
Answer:
51
Step-by-step explanation:
Answer:
42.5 units^2
Step-by-step explanation:
We can split up this shape into smaller ones.
First we can start with the large rectangle on top
We know its 9 by 3.5
9x3.5=31.5
The large rectangle is 31.5, at the end we'll add them all together
Next we can work on the small triangle on the bottom left
Area= bh/2
Both the base and height are 2, 2x2=4 4/2=2, The area of that triangle is 2
Now we can work on the triangle on the bottom right. This time the base is 5
5x2=10 10/2=5, The area of that triangle is 5
Now we need to figure out the square/rectangle at the bottom. We only know one side is 2. We can figure out the top side. Since the very top of the shape is 9, we know that the bottom side of the large rectangle also has to add to 9. We know the values 2 and 5. 2+5+x=9, the missing length that's there is 2.
Now we know the small square is 2 by 2. 2x2=4 The square's area is 4
Now we add them all up.
31.5+2+5+4=42.5
An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:
Given:

![\bold{Interval \ \[-6, 3\]}](https://tex.z-dn.net/?f=%5Cbold%7BInterval%20%5C%20%5C%5B-6%2C%203%5C%5D%7D)
To find:
Domain=?
Solution:
The
is a graphic over the
interval.
A<em><u> graph of the domain</u></em>
is indicated mostly by the <em><u>transformation </u></em>that <em><u>horizontal shifts</u></em> to combat
.

=|x-3|
Therefore, the final answer is "Option (D)".
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