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2 years ago

14

Think of the letter X as four vectors starting from the center and pointing outward. Label the four vectors starting from the to

p left and proceeding u, v, w, z.
(a) Does u times v point in or out of the page? (in/out)
(b) Does u times z point in or out of the page? (in/out)
(c) Compute u times w.

1 answer:

laila [671]2 years ago

5 0

Answer:

a) in

b) in

Step-by-step explanation:

The detailed explanation is attached below

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Which number is not a perfect square?<br> A. 4<br> B. 9<br> C. 111<br> D. 81

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Step-by-step explanation:

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The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to

zepelin [54]

Answer:

Answer in terms of a trigonometric function :

$h = \frac{20tan(19.9)}{0.4-tan(19.9)}$

Answer in figures

$h = 190.5 feet$

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

$tan (19.9)=\frac{h}{50+x} ---------------equation 1\\$

$tan (21.8)=\frac{h}{x}----------------equation 2$

From equation 2,

$x =\frac{h}{tan21.8}=\frac{h}{0.4}$

substituting the value of x into equation 1, we get

$tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}$

$tan 19.9=h\times \frac{0.4}{20+h}$

cross multiplying,

$20\times tan(19.9) +htan(19.9)=0.4h$

$20tan(19.9)= h(0.4-tan(19.9))$

$h= \frac{20tan (19.9)}{0.4-tan (19.9)}$

The height of the tower is $h= \frac{20tan (19.9)}{0.4-tan (19.9)}$ in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

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2 years ago

A maritime flag is shown. What is the area of the shaded part of the flag? Explain

Rom4ik [11]

Answer:

<em></em> $Area = 72in^2$ <em></em>

<em></em>

Step-by-step explanation:

<em>Your question is incomplete without an attachment (See attachment)</em>

Required

Determine the area of the shaded part

From the attachment;

<em>Assume that the shaded portion is closed to the right;</em>

<em>Calculate the Area:</em>

<em></em> $Area_1 = Length * Width$ <em></em>

<em></em> $Area_2 = 8in * (6in + 6in)$ <em></em>

<em></em> $Area_2 = 8in * 12in$ <em></em>

<em></em> $Area_1 = 96in^2$ <em></em>

<em></em>

<em>Next;</em>

<em>Calculate the Area of the imaginary triangle (on the right)</em>

<em></em> $Area_2 = \frac{1}{2} * base * height$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * (6in + 6in) * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 12in * 4in$ <em></em>

<em></em> $Area_2 = \frac{1}{2} * 48in^2$ <em></em>

<em></em> $Area_2 = 24in^2$ <em></em>

<em></em>

<em>Lastly, calculate the Area of the Shaded Part</em>

<em></em> $Area = Area_1 - Area_2$ <em></em>

<em></em> $Area = 96in^2 - 24in^2$ <em></em>

<em></em> $Area = 72in^2$ <em></em>

<em></em>

<em>Hence,</em>

<em>The area of the shaded part is 72in²</em>

3 0

2 years ago