There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
What you want to do for each of those is follow the formula, y-y[1]=m(x-x[1]). When I say y[1] and x[1], I mean the x and y values given. So the first one would be y-4=-3(x-(-1)). Then you solve for y by distributing the -3 to x and +1 (+1 because two negatives make a positive), making the equation
y-4=-3x-3. Then you subtract the 4. Answer #1. y=-3x-7.
#2.
y-1=1(x-4)
y-1=x-4
y=x-5
#3.
y-2=2(x-(-1))
y-2=2x+2
y=2x+4
Hope this helped you!
Answer:
When n=3 and x=−2 the answer is 11.
Step-by-step explanation:
Given:
Let p (n,x) be the function such that
To Find:
p (n,x) = p ( 3, -2) = ?
Solution:
Substituting n = 3 and x = -2 we get
Negative square gives positive number therefore (-2)²=4
When n=3 and x=−2 the answer is 11.
Answer:
Jane found multiples of 8.
Jane should have gotten 1, 2, 4, 8 as her answer.
Step-by-step explanation:
Factors : 1,2,4,8.
1*8=8
2*4=8
