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3 years ago

What was Fredrick Hoyle trying to find out?

Chemistry

1 answer:

joja [24]3 years ago

6 0

Answer:

Hoyle believed that as new matter forms,

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Find any errors in the orbital notation diagrams below and correct them.

riadik2000 [5.3K]

Answer:

See explanation.

Explanation:

A. 2s is incorrect, the right arrow should be pointing downwards.

B. In 2p, the last box has 3 arrows. This is invalid. Each box can only store 2 arrows(electrons). The last arrow should be moved to a 3p orbital (new box).

C. In this one, the arrows switched directions (left is down and right is up). You could fix each box or just the last one (in 3p) to point downwards.

4 0

3 years ago

if a person in a boat sailed straight across to other side of this lake, which of these statements would be true about the trip?

LUCKY_DIMON [66]

There’s no statements I can’t answer

4 0

3 years ago

What is the equilibrium vapor pressure of a liquid and how is it measured

weqwewe [10]

The equilibrium vapor pressure of a liquid is the pressure exerted by a vapor on the liquid at a given temperature. It is measured in atm.

8 0

4 years ago

Light elements with an atomic number less than 20 generally have a neutron to proton ratio equal to

Natalija [7]

Atomic elements consist of a nucleus that contains protons and neutrons. Protons carry a positive charge whilst neutrons are electrically neutral. In light elements with an atomic number less than 20, the neutron to proton ratio is generally equal to 1:1. This changes for heavier elements since the Coulomb interaction between many protons gets stronger and demands more neutrons for the nucleus to remain stable.

6 0

3 years ago

when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc

OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0

3 years ago