The answer would be
x^3 + 8x^2 + 19x + 39
x^3 + 8x^2 + 19x + 39
If right good review
2 answers:
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max is at vertex
in form
the x value of the vertex is
given,
a=6, b=0
the x value of the vertex is -0/(2*6)=0
the y value is
so vertex is at (0,-1)
since the value of a is positive, the parabola opens up and the vertex is a minimum value of the function
therefore that value is the smallest value the function can be
domain=numbesr you can use for x
range=numbesr you get out of inputting the domain
domain=all real numbers
range is {y | y≥-1} since y=-1 is the minimum