Answer:
Explanation:
From the given study,
the molecular formula of the given aromatic compound = C9H12
the first process we suppose to carry out is to calculate the double bond equivalence.
So, the double bond equivalence
DBE = 4
Hence, the aromatic compound possesses 4 double bonds, this signifies that the might be a presence of benzene ring.
The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.
Answer: (3) silicon
Explanation:
Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Silicon (Si)
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: ethane , propanone
and water
The number of sigma bonds = 5, and number of pi bonds = 3 in the given compound. Shown in attachment are the two Lewis structures of the compound with molecular formula C4H10. The two structures are the isomers of each other.
Butane is an alkane represented by C4H10. All the bonds in this situation are single bonds because this substance is an alkane. Two shared electrons are present in every bond.
Each carbon atom requires 8 electrons around it in order to follow the Octet Rule. The octet rule was completed by the hydrogen bonds, eliminating the need for the electron dots.
Straight-chained butane is the first structure. The y-chained isobutane is the second structure.
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