All categories

2 years ago

Chemitey half equations

Chemistry

1 answer:

shepuryov [24]2 years ago

8 0

Isn't it a because in b at the start of the equation the E in Fe just disappeared

You might be interested in

The nucleus contains both protons and electrons True or false

Varvara68 [4.7K]

Answer: False

Explanation: The nucleus of an atom only contains the protons and neutrons.

The electrons are not found in the nucleus,

they are orbiting the nucleus in different shells.

3 0

3 years ago

there are several ways to express solution concentration dilute concentrated ppm molarity molality normality all of these have o

klio [65]

B: quantity of solute with a specific volome of solvent.

Have a Nice Day :)

4 0

2 years ago

Read 2 more answers

Iron and carbon monoxide are made by heating 5.53 kg of iron ore, Fe₂O₃, and carbon. What is the theoretical yield of iron in ki

vfiekz [6]

Answer:

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow :

Fe2O3 + C → Fe + CO

Balance the equation

Fe2O3 + 3C → 2Fe + 3CO

compute the molecular mass of Fe2O3 and atomic mass of Iron(Fe)

Molecular mass of Fe2O3 = 55.845(2) + 15.999(3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3 produces 2 × 55.845 = 111.69 g of Fe(iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg = 5.53 × 1000 = 5530 g

since,

159.687 g of Fe2O3 produces 2 × 55.845 = 111.69 g of Iron(Fe)

5530 g of Fe2O3 will produce

cross multiply

Mass of Fe produced =5530 × 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069 g

convert to kg

1000 g = 1 kg

3867.85211069 = 3867.85211069/1000

Mass of Fe produced = 3.86785211069 ≈ 3.87 kg

3 0

3 years ago

What is the oxidation number of sulfur in H2SO3?<br> a. +3<br> b. +1<br> c. +2<br> d. +4

Alla [95]

We need to keep in mind that the compound is neutral.

H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4

Therefore the oxidation number for sulfur is +4.

3 0

3 years ago

Read 2 more answers

Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow

andreyandreev [35.5K]

Explanation:

(a) The given data is as follows.

Pressure on top ( $P_{o}$ ) = 140 bar = $1.4 \times 10^{7} Pa$ (as 1 bar = $10^{5}$ )

Temperature = $15^{o}C$ = (15 + 273) K = 288 K

Density of gas = $\frac{PM}{ZRT}$

$\frac{dP}{dZ} = \rho \times g$

$\frac{dP}{dZ} = \int \frac{PM}{ZRT}$

$\int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ$

$ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}$

= 0.4548

$P_{1} = P_{o} \times e^{0.4548}$

= $1.4 \times 10^{7} Pa \times 1.5797$

= $2.206 \times 10^{7} Pa$

Hence, pressure at the natural gas-oil interface is $2.206 \times 10^{7} Pa$ .

(b) At the bottom of the tank,

$P_{2} = P_{1} + \rho \times g \times h$

= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

= $309.8 \times 10^{5} Pa$

= 309.8 bar

Hence, at the bottom of the well at $15^{o}C$ pressure is 309.8 bar.

6 0

3 years ago