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oksian1 [2.3K]
3 years ago
7

DNA transcription-to-translation # 1 Homework Unanswered Due in 4 days Given the following sequence of the coding strand, writte

n in standard 5' to 3' orientation, locate the start codon. CGTTATGTGGACTCTCTGGTATGACTCACCTTAT Starting with and including the start codon, enter the sequence of protein that would be produced by this. Enter your answer without spaces and use single letter abbreviations for the amino acids.
Chemistry
1 answer:
uysha [10]3 years ago
3 0

Explanation:

Translation is the process by which a polypeptide is polymerized from genetic information.

Firstly we have to make a transcription from the coding DNA strand to a single RNA strand (mRNA). RNA pol reads from 5' to 3' of the template strand and nucleotides are added by complementarity ( Adenine with Uracil, Thymine with Adenine and Cytosine with Guanine, Guanine with Cytosine).

DNA:  5'-  CGTTATGTGGACTCTCTGGTATGACTCACCTTAT -3'

mRNA: 5'-GCAAUACACCUGAGAGACCAUACUGAGUGGAAUA -3'

mRNA goes to the ribosomes where translation takes place. The enzyme will read every three letters (codon) starting at the start codon sequence (TAC in DNA, AUG in mRNA). According to codons tRNA carrying the amino acids will place it (by complementary to their anticodon) and the enzyme will join it to the nascent polypeptide or protein.

In order to do this we need to look up the genetic code and assign the proper amino acids.

Unfortunately the given strand does not have a start codon TAC codifying for initial methionine.

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Type the correct answer in the box. The pressure inside a tire is measured as 28.0 . What is its pressure in ? 1 pound = 4.45 ne
posledela

The pressure is 19.3 N/cm².

<em>p</em> = (28.0 lb/1 in²) × (4.45 N/1 lb) × (1 in²/6.45 cm²) = 19.3 N/cm²

8 0
3 years ago
A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equa
Ilya [14]

Answer:

Percentage yield = 0.49 × 10² %

Explanation:

Given data:

Actual yield of SO₂ = 4.309 ×10² g

Theoretical yield of SO₂ = 8.78 ×10² g

Percentage yield = ?

Solution:

Chemical equation:

2NiS₂ + 5O₂ → 2NiO + 4SO₂

Percentage yield:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 4.309 ×10² g  / 8.78 ×10² g  × 100

Percentage yield = 0.491 × 100

Percentage yield = 49.1%

In scientific notation:

Percentage yield = 0.49 × 10² %

5 0
3 years ago
Find the volume of 0.100M hydrochloric acid necessary to react completely with 1.51g Al(OH)3.
shtirl [24]
Reaction equation:
Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O
Moles of Al(OH)₃:
moles = mass/Mr
= 1.51 / (27 + 17 x 3)
= 0.019
Molar ratio Al(OH)₃ : HCl = 1 : 3
Moles of HCl required = 0.019 x 3
=0.057
concentration = moles/volume
volume = 0.057 / 0.1
= 0.57 dm³
= 570 ml
3 0
3 years ago
A 5.00-L tank contains helium gas at 1.50 atm. What is the pressure of the gas in mmHg
bulgar [2K]

Answer:

  1140 mmHg

Explanation:

1 atmosphere is 760 mmHg, so 1.5 atmospheres is ...

  1.5×760 mmHg = 1140 mmHg

4 0
3 years ago
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
2 years ago
Read 2 more answers
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