C. Forces cannot be quantified
Forces always act in pairs and are subject to change
Answer: 6.25 m/s^2
Explanation:
The distance between Vinny and the ramp is 200m
And he has 8 seconds (At max) to reach that distance.
The initial velocity is 0m/s
The initial position is 0m
Now, we want to find the constant acceleration in order to do this, so suppose that we have a constant acceleration A.
a(t) = A.
To have the velocity, we must integrate over time, and remember that the constant of integration is equal to zero because the initial velocity is zero.
v(t) = A*t
For the position, we integrate again over time.
p(t) = 0.5*A*t^2
And we want to travel 200m in 8 seconds, then:
p(8s) = 200m
0.5*A*(8s)^2 = 200m
A*32s^2 = 200m
A = 200m/32s^2 = 6.25 m/s^2
This is the minimum acceleration in order to do this, if Vinny has a larger acceleration he will travel the 200m in a smaller time.
Answer:
I've never been in a earthquake
The greatest point for kinetic is at the bottom and in the middle it is in half and at the top it is at the highest in potential energy.
2Fe(s) + O2 -> 2FeO(s)
<span>2 'Fe' atoms on both sides </span>
<span>2 'O' atoms on both sides</span>
