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There should be an image that should accompanied your question, I was able to chcek it from other sources. the acceleration of the block when the scale reads 32N is <span>4.0 m/s*s</span>
Answer:
Current will decrease.
Explanation:
When we increase the number of stepping in transformer, the voltage will increase as its is directly proportional to the number of turn of stepping. Thus as the voltage will increase, current will decrease. As per the equation of ideal transformer, E1 / E2 = I2 / I1
E1 and E2 are the voltages in primary and secondary winding and I1 and I2 are the current.
As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.
Though the conservation of energy is obeyed but losses occur in this scenario hence step-up transformers cannot be used to create free energy.
Answer:
d₁ = 0.29 in
d₂ = 0.505 in
Explanation:
Given:
T = 1500 lbf in
L = 10 in
x = 0.5 L = 5 in

First case: T = T₁ + T₂
T₂ = T - T₁ = 1500 - 750 = 750 lbf in
If the shafts are in series:
θ = θ₁ + θ₂
θ = ((T₁ * L₁)/GJ) + ((T₂ * L₂)/GJ)
Second case: If d₁ ≠ d₂
θ = ((T₁ * L₁)/GJ₁) + ((T₂ * L₂)/GJ₂) = 0 (eq. 1)
t₁ = t₂
(eq. 2)
T₁ + T₂ = 1500 (eq. 3)
θ₁ first case = θ₁ second case
Replacing:

The same way to θ₂:

From equation 2, we have:
d₁ = 0.587 * d₂
From equation 3, we have:
d₂ = 0.505 in
d₁ = 0.29 in
Answer:
a) 
b) 
Explanation:
From the exercise we know that



From dynamics we know that the formula for average velocity is:

a) For the three intervals:



b) The average velocity for the entire motion can be calculate by the following formula:

Answer: 3MeV electron
Explanation:
m_e={9.1\times 10^{-31} m_α=4\times m_e m_a={9.1\times 10^{-31}
m_p=1.67\times 10^{-27}
(a) K.E. Energy of electron =
=3MeV
=1.05\times10^{18}

(b) K.E. Energy of alpha particle =
=10MeV
=0.88\times10^{18}

(c) K.E. Energy of auger particle =
=0.1MeV
=0.035\times10^{18}

(d) K.E. Energy of proton particle =
=400keV
=0.766\times10^{14}
![v_p=\sqrt{0.766\times10^{14} } =0.875\times10^{7}[tex]\frac{m}{s}](https://tex.z-dn.net/?f=v_p%3D%5Csqrt%7B0.766%5Ctimes10%5E%7B14%7D%20%7D%20%3D0.875%5Ctimes10%5E%7B7%7D%5Btex%5D%5Cfrac%7Bm%7D%7Bs%7D)
from (a),(b),(c),and (d) we can clearly say that the velocity of the electron is more so the penetration of the electron will be deepest.