Answer:
80 miles per 80 miles per hour so Likud those up So the kid throws up
Answer:
0.7 secs
Explanation:
In this question, the speed does not change as the mass changes. So we can use
Δ<em>t=Δ∨x/χgμ............................equ 1</em>
To stop, the final speed will be 0
Therefore,
<em>Δvx=vf-vt</em>
Δvx=0-4m/s
= -4m/s
Now substitute the various values in equ 1
Δ<em>t=Δ∨x/χgμ</em>
Δ<em>t= -</em>4m/s/(9.8m/s∧2) (0.6)
Δ<em>t=</em>0.7 secs
By conservation of momentum, the initial recoil speed of the
rifle is:
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s
The final recoil speed v is zero in a distance of d = 0.0346 m
So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323
m/s^2
a = -114.07m/s^2
