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fomenos
3 years ago
11

Help I need Help bad

Physics
1 answer:
sukhopar [10]3 years ago
7 0
C to D. And E to F. Going back to point of origin

A to B she is traveling faster, y axis (distance) change vs. x axis of time is graphs steepest incline.
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Which of the following is NOT a recommended change in physical activity for aging individuals? A. taking a longer time to warm u
REY [17]

participating only in cardiovascular exercises

7 0
3 years ago
In the process of loading a ship, a shipping container gets dropped into the water and sinks to the bottom of the harbor. Salvag
jolli1 [7]

Answer:

57.885.8 kg   weight of the container

Explanation:

The volume of the balloon * density of water = buoyant force of balloon

 volume of a sphere = 4/3 pi r^3

                                   = 4/3 pi * (1.5)^3 = 14.14 m^3   <===balloon volume

Now,   find the buoyant force on the container ALONE ....

             5.8 * 2.6 * 2.8  * 1027  = 43 364  kg   <=====  buoyant force

Now add the buoyant force of the balloon to find the weight

             43 364  +   14.14 * 1027 = 57885.8   kg

3 0
2 years ago
A Ferris wheel has a radius of 25 feet. The wheel is rotating at two revolutions per minute. Find the linear speed, in feet per
svet-max [94.6K]
Linear velocity and angular velocity are related by the formula:
v = ωr

ω = n2πr/t, where n is the number of rotations, t is the time taken, r is the radius.
ω = 2 x 2π x 25/1
ω = 100π

v = 100π x 25
= 2500π feet per minute
8 0
4 years ago
A 1,500.0 kg car hits a brick wall with a force of 60.0 N in 1.75 seconds. What is the change in the momentum of the car?
mel-nik [20]

105 kg m/s

Explanation:

The change in momentum of the car is equal to the impulse, which is equal to the product between the force applied and the time of the collision:

\Delta p= F \Delta t

in this case, the force applied is F=60.0 N, while the time of the collision is \Delta t=1.75 s, so the change in momentum of the car is

\Delta p=(60.0 N)(1.75 s)=105 kg m/s

7 0
4 years ago
Read 2 more answers
: A fan is placed on a horizontal track and given a slight push toward an end stop 1.80 meters away. Immediately after the push,
Leokris [45]

Answer:

The initial velocity is 1.27 m/s.

Explanation:

distance, s = 1.8 m

acceleration, a = - 0.45 m/s^2

final velocity, v = 0

let the initial velocity is u.

Use third equation of motion

v^2 = u^2 + 2 a s \\\\0 = u^2 - 2 \times 0.45\times 1.8\\\\u = 1.27 m/s

7 0
3 years ago
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