Answer:
Mass of the aluminium chunk = 278.51 g
Explanation:
For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same
A specific heat formula is given as
Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature
Q = m×c×ΔT
Heat gain by aluminium + heat lost by copper = 0 (1)
For Aluminium:
Q =
Q = m x 17.94 joule
For Copper:
Q= 4996.53 Joule
from eq 1
m x 17.94 = 4996.53
Mass of the aluminium chunk = 278.51 g
<span>Gvn that,
Radius r = 1.65cm
then the Diameter d = 3.3 cm
Volume V = 4/3pi*(D/3)^3
= 4/3*3.14*(3.3)^3/8
= 4/3*3.14*35.937/8
= 4/3*3.14*4.492125
= 4/3*14.1052725
= 56.421.9/3
= 18.80703 dm^3
We know that gravity g=9.806m/s^2
p pt = 2.14 * 104 kg/m^3 = 21.4
p hg = 1.36 * 104 kg/m^3 = 13.6
Real Weight Wr = V*p pt*g
= 18.80703*21.4*9.806
= 3946.625 N
Buoyant force Fb= V*p hg*g
= 18.80703*13.6*9.806
= 2508.136 N
Apparent weight = Wr-Fb
= 3946.625-2508.136
= 1438.489 N
Therefore Apparent weight is 1438.489 N</span>
Answer:
from outside of the bottle to inside is by conduction and bottom to tha top of the water is by convection
Answer:
3,97078708130496x10^16 meters.
Explanation:
First of all you have to know the light speed which is approximately .
Next you have to know the distance formula that is d = s * t. d stands for distance, s stands for speed, and t stands for time.
Now you have the speed of light that was given above, but, you have time in years and need it to be in seconds to be suppressed with the speed seconds. So we calculate the time in seconds.
For 1 day, you have 24 hours, that's equal to 1440 minutes, that's equal to 86400 seconds. So, using a simple three rule if 1 day is equal to 86400 seconds, 365 days is equal to 31536000 seconds.
Now, you multiply that result ( 31536000 seconds) times 4.2 (Which is the time that takes it to reach the Earth), and you get 132451200 seconds.
Next step is to simply replace the values in the formula, and do the multiplication.
Have a nice day.
Answer:
Vi = 8.28 m/s
Explanation:
This problem is related to the projectile motion.
As we know there are two components of motion associated with this, the horizontal component and vertical component.
The horizontal distance covered by the ball is
Vx*t = x
Vx*t = 5.3
Vx = 5.3/t eq. 1
Also we know that
Vx = Vicos(60)
Vx = Vi*0.5 eq. 2
equate eq. 1 and eq. 2
5.3/t = Vi*0.5
5.3/0.5 = Vi*t
Vi*t = 10.6 eq. 3
The vertical distance is
Vy = y1 + Vyi*t - 0.5gt²
also we know that
Vyi = Visin(60)
Vyi = Vi*0.866
It is given that V1 = 1.9 m and and Vy = 3 m is the vertical distance
3 = 1.9 + Vi*0.866*t - 0.5gt²
3 = 1.9 + Vi*0.866*t - 0.5(9.8)t²
3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²
3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²
1.1 = 0.866(Vi*t) - 4.9t²
0.866(Vi*t) = 4.9t² + 1.1
substitute Vi*t = 10.6 in above equation
0.866(10.6) = 4.9t² + 1.1
9.18 = 4.9t² + 1.1
4.9t² = 8.08
t² = 8.08/4.9
t² = 1.648
t = 1.28 sec
Finally, initial speed can be found by substituting the value of t into eq. 3
Vi*t = 10.6
Vi = 10.6/t
Vi = 10.6/1.28
Vi = 8.28 m/s