Question

18. A rock is thrown straight upward with an initial velocity of 12.2 m/s from a location where the acceleration due to gravity is 9.8 m/s2. How high up does it go

Answer 1

The height to which the rock can attain is 7.6 m

From the question given above, the following data were obtained:

Initial velocity (u) = 12.2 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =?

The maximum height to which the rock can attain can be obtained as follow:

v² = u² – 2gh (since the rock is going against gravity)

0² = 12.2² – (2 × 9.8 × h)

0 = 148.84 – 19.6h

Collect like terms

0 – 148.84 = – 19.6h

–148.84 = –19.6h

Divide both side by –19.6

h = –148.84 / –19.6

h = 7.6 m

Thus, the height to which the rock can attain is 7.6 m

Learn more: brainly.com/question/25711946