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2 years ago

Three balls with the same radius 21 cm are in water. Ball 1 floats, with

Physics

1 answer:

Masteriza [31]2 years ago

7 0

Answer:

Explanation:

A )

The ball floats with half of it exposed above the water level . So it must have density half that of water . In other words its density must have been 500 kg / m³

B )

Tension in the ball will be equal to net force acting on the ball

Net force on the ball = buoyant force - weight .

4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1000 - 893 )

= 40.65 x 10⁻⁶ N .

C )Tension in the 3 rd ball will be equal to net force acting on the ball

Net force on the ball = weight - buoyant force

= 4/3 x π x .21³ x 10⁻⁶ x 9.8 ( 1320 - 1000 )

= 121.6 x 10⁻⁶ N .

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krok68 [10]

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m therefore r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

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<u>Determine the metacentric height </u>

weight of cylinder in water = water displaced

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= 0.6 * 4 = h

∴ h = 2.4 m

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The metacentric height can be calculated using the formula below

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2 years ago

. The inner and outer surfaces of a 4-m × 7-m brick wall of thickness 30 cm and thermal conductivity 0.69 W/m-K are maintained a

Anni [7]

Answer:

$\frac{dQ}{dt} = 966 W$

Explanation:

As we know that the rate of heat transfer due to temperature difference is given by the formula

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here we know that

$K = 0.69 W/m-K$

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$\frac{dQ}{dt} = 966 W$

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2 years ago

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marin [14]

Answer:

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3 years ago

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Answer:

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3 years ago

If a ball leaves the ground with a vertical velocity of 5.46 m/s, how long does it take

kifflom [539]

Answer:

0.557 s

Explanation:

Given:

v₀ = 5.46 m/s

v = 0 m/s

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3 years ago