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Svetlanka [38]
2 years ago
7

The lower your salary, the less efficient you are. This represents a ______

Chemistry
2 answers:
creativ13 [48]2 years ago
7 0

Answer:

I believe that it is a negative correlation

kari74 [83]2 years ago
3 0

Answer:

the answer is False. The false cause fallacy occurs when we wrongly assume that one thing causes something else.

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Gwar [14]

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encerio soy la única que habla español?

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2 years ago
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Consider the chemical equilibrium of the reaction. NH4OH(aq) mc014-1.jpg NH4+(aq) + OHmc014-2.jpg(aq) What will happen to the ch
Bingel [31]
The chemical equilibrium will shift to the left.
Since NH4+ ions are a product of the original reaction, increasing their concentration will shift the equilibrium toward the reactants.
8 0
3 years ago
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Tamara is studying the human digestive system in science class. A diagram similar to the one that follows appears in her text bo
grin007 [14]

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esophagus

Explanation:

just took the test

8 0
3 years ago
PLEASE PLEASE HELPPP ITS DUE SOON ILL GIVE BRAINLIEST
gayaneshka [121]

Answer:

Explanation:

Using at least three sentences,, explain the four stages involved in genetic engineering/gene cloning.

Stage 1: Isolation of the target gene

Stage 2: Insertation of the target gene

Stage 3: Introduction of the vector into a host

Stage 4: Amplification of the target gene by the host cell and screening

8 0
3 years ago
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
natali 33 [55]

Answer:

There are 0.93 g of glucose in 100 mL of the final solution

Explanation:

In the first solution, the concentration of glucose (in g/L) is:

15.5 g / 0.100 L = 155 g/L

Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.

  • 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)

The concentration of the second solution is:

155 \frac{g}{L} *\frac{0.030L}{0.500L}=9.3\frac{g}{L}

So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:

1 L --------- 9.3 g

0.1 L--------- Xg

Xg = 9.3 g * 0.1 L / 1 L = 0.93 g

8 0
3 years ago
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