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Nonamiya [84]
3 years ago
8

You see a used car you wish to buy. The dealer quotes you a price of $11,550. You have a blue book quotation of $8,400 for the s

ame model and year. How much markup on cost is the dealer using?
Mathematics
2 answers:
irga5000 [103]3 years ago
7 0
The dealer is charging $3150 markup
patriot [66]3 years ago
3 0

Answer:

37.5%

Step-by-step explanation:

We have been given that the dealer quotes you price of a car $11,550. You have a blue book quotation of $8,400 for the same model and year.

First of all, we will subtract the blue book quotation price from the price quoted by dealer to get the amount of markup.

\text{Mark-up}=\$11,550-\$8,400

\text{Mark-up}=\$3,150

Now, we will find $3,150 is what percent of $8,400.

\text{Mark-up percent}=\frac{\$3150}{\$8400}\times 100

\text{Mark-up percent}=0.375\times 100

\text{Mark-up percent}=37.5\%

Therefore, the dealer is using 37.5% of markup on the cost.

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Answer:

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Step-by-step explanation:

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3 years ago
To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to th
Nata [24]

the height of the house is 408ft .

<u>Step-by-step explanation:</u>

Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find  What is the height of the house . Let's find out:

Let  y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.

Distance of house from point A( initial point ) = x ft

Distance of house from point B( when she traveled 200 ft towards street  = x-200 ft

Now , According to question these scenarios are of right angle triangle as

At point A

⇒ Tan32 =\frac{Perpendicular}{Base}= \frac{y}{x}

⇒ Tan32 = \frac{y}{x}

⇒ y=x(Tan32 )       ..................(1)

Also , At point B

⇒ Tan42 = \frac{y}{x-200}

⇒ y=(x-200)(Tan42)     ..............(2)

Equating both equations:

⇒ (x-200)(Tan42) = x(Tan32)

⇒ x(Tan42-Tan32)=Tan42(200)

⇒ x=\frac{Tan42(200)}{(Tan42-Tan32)}

⇒ x=653ft

Putting  x=653ft in  y=x(Tan32 )  we get:

⇒  y=x(Tan32 )    

⇒  y=653(Tan32 )

⇒  y=408ft

Therefore , the height of the house is 408ft .

4 0
3 years ago
At one​ store, Julia saved ​$10 with a coupon for 40​% off her total purchase. At another​ store, the ​$29 she spent on books is
barxatty [35]
Let "a" and "b" represent the values of the first and second purchases, respectively.
  0.40*(original price of "a") = $10
  (original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
  a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
  a = $25.00 -10.00 = $15.00

At the other store,
  $29 = 0.58b
  $29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate

Then Julia's total spending is
  a + b = $15.00 +50.00 = $65.00

Julia spent $65 in all at the two stores.
6 0
3 years ago
The FOIL method is used to multiply a binomial by a binomial.<br> True<br> O<br> False
riadik2000 [5.3K]

Answer:

True

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A bakery sells 4 dozen cupcakes every 3 hours. If the bakery is open 8 hours each day, how many days does it take to sell 640 cu
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5 days does it take to sell 640 cupcakes.

Given:

A bakery sells 4 dozen cupcakes every 3 hours.

If the bakery is open 8 hours each day.

4 dozen cupcakes = 4*12 cupcakes

= 48 cupcakes

48 cupcakes = 3 hours

divide by 3 on both sides

3hours/3 = 48/3 cupcakes

1 hour = 16 cupcakes

Number of cupcakes for 8 hours = 8 * 16 = 128 cupcakes.

128 cupcakes sells in one day.

To sell 640 cupcakes = 640/128

= 5 days.

Therefore 5 days does it take to sell 640 cupcakes.

Learn more about the bakery and cupcakes here:

brainly.com/question/14466478

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8 0
1 year ago
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