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ycow [4]
3 years ago
12

two mechanics worked on a car. The first mechanic worked for 10 hrs, and the second mechanic worked for 5 hours. Together they c

harged a total of $1475. What was the rate charged per hour by mechanic if the sum of the two rates was $190 per hour? What is the first mechanic make per hour? And what did the second mechanic make per hour?
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

The first mechanic $90/hour and the second charged $70/hour

Step-by-step explanation:

Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:

5x+10y = 1150

We also know that together they charged 160/per hour. An equation to express this would be:

x+y = 160

Now we can solve the second equation for x or the first mechanics rate.

x+y = 160

x = 160 - y

Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.

5x+10y=1150 plug in x =160-y

5(160-y)+10y=1150 Distribute

800 -5y+10y = 1150 Combine like terms

800 +5y = 1150 Subtract 800 from both sides

5y = 350 divide by 5

y = 70

So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.

x = 160-y

x = 160-70

x = 90

So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.

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Charlie paid 660 for 6 shirts and four belts. One shirt costs three times as much as one belt. If Sam bought 5 shirts and 2 suck
Cerrena [4.2K]

Sam would have to pay $510 to buy 5 shirts and 2 suck belts.

Step-by-step explanation:

Let,

Cost of one shirt = x

Cost of one belt = y

According to given statement;

6x+4y = 660    Eqn 1

x = 3y          Eqn 2

Putting value of x from Eqn 2 in Eqn 1

6(3y)+4y=660\\18y+4y=660\\22y=660

Dividing both sides by 22

\frac{22y}{22}=\frac{660}{22}\\y=30

Putting y=30 in Eqn 2

x=3(30)\\x=90

One shirt costs $90 and one belt cost $30.

Price of 5 shirts = 90*5 = $450

Price of 2 belts = 30*2 = $60

Total = 450+60 = $510

Sam would have to pay $510 to buy 5 shirts and 2 suck belts.

Keywords: linear equation, addition

Learn more about addition at:

  • brainly.com/question/9381111
  • brainly.com/question/9369548

#LearnwithBrainly

6 0
3 years ago
Solve for X. Grade 7 math.
Dimas [21]

Answer:

x=8

Step-by-step explanation:

9x - 8 = 64 (being vertically opposite angles)

9x = 64 + 8

x=72/9

x=8

9x -8

9*8 -8

72-8

64

8 0
3 years ago
(06.01 MC)
anastassius [24]

Answer:

It is not a square because the side lengths are not the same length. It is a rectangle.

Step-by-step explanation:

4 0
3 years ago
The length of a rectangle is 3 units shorter than one-third of the width, x. Enter an expression in the box that represents the
cluponka [151]
Since length is 3 less than 1/3 width, set up equation l=(1/3)w-3. Because P=2(l+w), substitute l with the euation and get P=2(4/3w-3)
7 0
3 years ago
Read 2 more answers
Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

log_22 = 1

So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

6 0
3 years ago
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