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Elza [17]
3 years ago
12

Mr Cain is adding a home security system that will constantly use 5mbps of his 23mbps plan. How many of his mobile phones can al

so be used if his blue work phone and laptop must always be on ?
Computers and Technology
1 answer:
timofeeve [1]3 years ago
4 0

If Mr. Cain subscribes to a 23mbps (megabyte per second) plan it will only take 4 seconds for it to get exhausted by the security system which consumes 5mbps.

This means that none of the other gadgets will be able to connect because (all things being equal) it takes an average of 4 seconds for a device that is already set up on the network to get connected to wifi.

In those 4 seconds, the subscription would have been exhausted.

<h3>What is a home security system?</h3><h3 />

This refers to a collection of electronic devices which are collectively configured to protect a home. A home security system will usually comprise of the following:

  • Motion Sensor
  • Smart Camera
  • Alarm
  • Entry Sensor
  • Glass damage sensor
  • Panic Button
  • Base Station
  • Key fob
  • Keypad
  • Carbon Monoxide and Smoke detectors

In summary, to get all his gadgets connected, Mr. Cain would have to get an internet service plan that is way bigger than 23mbps.

See the link below to learn more about Home Security Systems:

brainly.com/question/1733069

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Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

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//  loop executed till value of k becomes equal to value of n

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Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

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When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

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