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kipiarov [429]
3 years ago
12

0.01040 m as an integer

Chemistry
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:

Here,

0.01040 m as an integer= 1.04 × 10-2

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If the crucible originally weighs 3.715 g and 2. 000 g of hydrate are added to it , what is the weight of the water that is lost
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For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.

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Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).

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