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nordsb [41]
3 years ago
6

Make x the subject of y = 4x + 1​

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

<h2>x=y-1/4</h2>

Step-by-step explanation:

y=4x+1            

-1

y-1=4x

divide by 4

y-1/4=x

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Determine the domain of the function, and then graph it.
Tomtit [17]
First set change the function f(x) to y so
that it would be
y = \sqrt{x + 4} - 1
Then set y = 0
0 = \sqrt{x + 4} - 1
Then solve for x

X = - 3

To graph it, just plot the point (-3,0) on the x-axis
6 0
3 years ago
Determine if each ratios or rates are equivalent.
maxonik [38]

Answer:

no these are not equivalent

Step-by-step explanation:

these aunt equivalent because 12+12 =24 and 3+3=6 not 7 or 28 so no ccx these are not equivalent

4 0
3 years ago
To rent a certain meeting room, a college charges a reservation fee of $34 and an additional fee of $9.70 per hour. The history
Flauer [41]

Answer:

t=5

Step-by-step explanation:

34+9.70t=82.50

-34 -34.00

9.70t=48.50

divide 9.70 from both sides

t=5

3 0
3 years ago
Mr.Robinson ordered 4 cheeseburgers for $2.95 each and 4 sodas for $1.59 each. If he paid with a $20 bill, how much change did h
Fynjy0 [20]
4 x 2.95 = 11.80$
4 x 1.59 = 6.36$
11.80 + 6.36 = 18.16 $
20 - 18.16 = 1.84

Mr. Robinson will get $1.84 in change
5 0
2 years ago
Read 2 more answers
PLEASE SOLVE THIS PROBLEM ​
schepotkina [342]

Answer:

18) Area= 5*5/2=25/2=12.5 unit ^2

19) Area=AB^2V3/4=8a^2*V3/4=2V3a^2

Step-by-step explanation:

18. A(-3,0)

B(1,-3)

C(4,1)

AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5

AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2

BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5

so AB=BC=5

and AC^2=AB^2+BC^2

so trg ABC is an isosceles right  angle triangle (<B=90)

Area= 5*5/2=25/2=12.5 unit ^2

19. A(a,a)

B(-a,-a)

C(-V3a, V3a)

AB=V(a+a)^2+(a+a)^2=V4a^2+4a^2=V8a^2

AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2

BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2

so AB=AC=BC

Area=AB^2V3/4=8a^2*V3/4=2V3a^2

7 0
3 years ago
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