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2 years ago

What project did mary jackson work on at naca soon after she was hired?.

Mathematics

2 answers:

earnstyle [38]2 years ago

5 0

Answer:

After two years in the computing pool, Mary Jackson received an offer to work for engineer Kazimierz Czarnecki in the 4-foot by 4-foot Supersonic Pressure Tunnel, a 60,000 horsepower wind tunnel capable of blasting models with winds approaching twice the speed of sound.

SO this answer would be C.

Step-by-step explanation:

saw5 [17]2 years ago

3 0

The project Mary Jackson worked on at nasa soon after she was hired was landing astronauts on the moon and how to return them safely back to earth.

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You are going shopping. You are given 40 dollars to buy clothing. You buy

Oduvanchick [21]

Answer:

6 dollars

Step-by-step explanation:

40-10=30

30/5= 6

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3 years ago

Read 2 more answers

Solve the equation for X.

Svetllana [295]

Answer:

x = - $\frac{11}{8}$

Step-by-step explanation:

Given

(x - 4) - (x + 7 ) = 8x

Distribute parenthesis noting second is distributed by - 1

x - 4 - x - 7 = 8x ← simplify left side

- 11 = 8x ( divide both sides by 8 )

x = - $\frac{11}{8}$

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3 years ago

Diane is culturing bacteria that have a growth rate of 15% per hour. If the current population is 24,000 bacteria, how many bact

slamgirl [31]

Answer: 60,000

Step-by-step explanation: 24,000 plus 150% = 60,000

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3 years ago

POSSIBLE OUTCOMES!!!

Ganezh [65]

The probability of drawing two blue marbles if the first marble is not replaced is 1/5

<h3>How to determine the probabilities?</h3>

<u>The probability of tossing a head and drawing a red marble</u>

The given parameters are:

White = 1

Blue =3

Red = 2

Total = 6

The probability of a head is

P(Head)= 1/2

The probability of drawing a red marble is

P(Red)= 2/6 = 1/3

The required probability is

P = P(Head) * P(Red)

This gives

P = 1/2 * 1/3

P =1/6

<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>

Here, we have:

P(B1) = 3/6 = 1/2

P(B2) = 2/5

The required probability is

P = P(B1) * P(B2)

This gives

P = 1/2 * 2/5

P =1/5

Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5