Answer:
<em><u>Answer is below</u></em>
Step-by-step explanation:
<u><em>3+5(2−3)−6</em></u>
<u><em>=3+(5)(−1)−6</em></u>
<u><em>=3+−5−6</em></u>
<u><em>=3+−11</em></u>
<u><em>=−8</em></u>
<u><em>So therefore, your answer would be -8</em></u>
Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
For any x in Real numbers, [x] is the greatest possible integer smaller than x, or equal to x if x is an integer.
According to this,
<span>[2.4] is the greatest integer , smaller than or equal to (so non greater) 2.4. This number is 2
similarly, </span>[-2.4] is the greatest integer , smaller than or equal to (so non greater) -2.4. This number is -3.
Answer:
A) <span>Because 2 is the greatest integer not greater than 2.4 and –3 is the greatest integer not greater than –2.4. </span>