Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
<em />
You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
I believe it is four dollars
Answer:
f(- 6) = 9
Step-by-step explanation:
to evaluate f(- 6), substitute x = - 6 into f(x)
f(- 6) = -
× - 6 + 5
= -
+ 5 = 4 + 5 = 9
Answer:
they need 25 more signatures to get their idea carried out
Step-by-step explanation: 25% of 426 is 107 and 107 minus 82 is 25
12!!!! Hope this helped and good encouragement