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kramer
2 years ago
13

Water pumps use electrical energy to create mechanical energy needed to move water.

Physics
1 answer:
Afina-wow [57]2 years ago
3 0

Answer:

n/a

Explanation:

this question is not feasible

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Why should people pay attention to scientists when making decisions? A)scientist are the smartest people B) Scientist make up fa
MrRa [10]

Answer:

C) scientist use experiments to test their ideas

3 0
3 years ago
Read 2 more answers
Why it is easier to remove a 2p electron from an oxygen atom than from a nitrogen atom?
DedPeter [7]

Answer:

The electrons in oxygen are paired while in nitrogen, they are not.

Explanation:

To analyse this we start with writing out the ground state electronic configurations for both elements.

Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons                  ↑↓   ↑   ↑

Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons  ↑    ↑    ↑

Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied

7 0
2 years ago
Select the correct answer.
Gekata [30.6K]

Answer:

A.

Explanation:

an atom that has most of its mass is electrons.

6 0
3 years ago
When the mass is removed, the length of the cable is found to be l0 = 4.66 m. After the mass is added, the length is remeasured
zaharov [31]

Answer:

\gamma=6.07*10^5\frac{N}{m^2}

Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

\gamma=\frac{F/A}{\Delta L/L_0}

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, \Delta L is the amount by which the length of the object changes and  L_0 is the original length of the object. In this case the force is the weight of the mass:

F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N

Replacing the given values in Young's modulus formula:

\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}

6 0
2 years ago
The Atoms Family
ioda
What question are you asking?
4 0
2 years ago
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