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julia-pushkina [17]
3 years ago
13

Precipitation is most likely occurring at A because it is located

Physics
1 answer:
Dovator [93]3 years ago
4 0
The answer is C. Near the cold front
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If gas costs $3.65 per gallon at a local service station, how many cubic feet of gas can a customer buy with $40 ?
svet-max [94.6K]
Hi, thank you for posting your question here at Brainly. 

For consistency you must convert gallons to cubic foot. The conversions are:

7.481 gal = 1 ft3

Then, $3.65 per gallon becomes $27.3 per ft3. If you buy $40 worth of gas, you get $40/$27.3 = 1.46 ft3 of gas. 

If you can travel for 4 miles per ft3, then with the amount of gas you have, you can travel up to 5.85 miles.

(4 miles/ft3)*(1.46 ft3) = 5.85 miles
3 0
3 years ago
The two waves shown here are the same distance from point x and are traveling toward each other
kompoz [17]

The Answer should be A: 0.0

3 0
3 years ago
Read 2 more answers
Ramas weight is 40 kg. She is carrying a load of 20 kg up to a height of 20 m. What work does she do? What work does she do?
Taya2010 [7]

Answer:

The work done by Ramas is 3920 N.

Explanation:

Given;

mass of the load lifted by Ramas, m = 20 kg

height through which the load is lifted, h = 20 m

The work done by Ramas is equal to gravitational potential due to the height in which the load is lifted.

W = PE = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

W = 20 x 9.8 x 20

W = 3920 N.

Therefore, the work done by Ramas is 3920 N.

3 0
3 years ago
An object moves in a straight path. Its position x as a function of time t is presented by the equation x(t) = at – bt2+c, where
ankoles [38]

Answer:

The answer is below

Explanation:

Given that:

x(t) = at – bt2+c

a) x(t) = at – bt2+c

Substituting a = 1.4 m/s, b = 0.06 m/s2 and c =50 m gives:

x(t) = 1.4t - 0.06t² + 50

At t = 5, x(5) = 1.4(5) - 0.06(5)² + 50 = 55.5 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

v=\frac{x(5)-x(0)}{5-0}\\ \\v=\frac{55.5-50}{5-0}=1.1\\ \\v=1.1\ m/s

b) x(t) = 1.4t - 0.06t² + 50

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

At t = 0, x(0) = 1.4(0) - 0.06(0)² + 50 = 50 m

The average velocity (v) is given as:

v=\frac{x(10)-x(0)}{10-0}\\ \\v=\frac{58-50}{10-0}=0.8\\ \\v=0.8\ m/s

c) x(t) = 1.4t - 0.06t² + 50

At t = 15, x(5) = 1.4(15) - 0.06(15)² + 50 = 57.5 m

At t = 10, x(10) = 1.4(10) - 0.06(10)² + 50 = 58 m

The average velocity (v) is given as:

v=\frac{x(15)-x(10)}{15-10}\\ \\v=\frac{57.5-58}{15-10}=0.1\\ \\v=0.1\ m/s

6 0
3 years ago
In Hooke’s law, what does k represent?
notsponge [240]
I believe the k value represents the D. Stiffness of the spring.
7 0
3 years ago
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