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Grace [21]
3 years ago
14

How many moles of MgCO3 are in 2.57g of MgCO3?

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

  • MgCO₃ MW = Atomic mass Mg + Atomic mass C + (Atomic mass O)*3
  • MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we <u>divide the mass by the molecular weight</u>, to calculate the <em>number of moles</em>:

  • 2.57 g MgCO₃ ÷ 84.3 g/mol = 0.0305 moles.
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