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Grace [21]
3 years ago
14

How many moles of MgCO3 are in 2.57g of MgCO3?

Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

  • MgCO₃ MW = Atomic mass Mg + Atomic mass C + (Atomic mass O)*3
  • MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we <u>divide the mass by the molecular weight</u>, to calculate the <em>number of moles</em>:

  • 2.57 g MgCO₃ ÷ 84.3 g/mol = 0.0305 moles.
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B

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What does the number 84 in the name krypton 84 represent
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The volume of 1.20 lol of gas at 61.3 kPa and 25.0 degree Celsius is
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Answer:

V = 48.5 L

Explanation:

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T = 25.0°C + 273.15 = 298.15 K

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V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm

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4 0
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What's the chemical equation for the carbon dioxide bubbles in a homemade lava lamp?
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When you drop tablet into water the citric acid reacts with sodium bicarbonate and forms water, a salt, and bubbles of carbon dioxide gas.

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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
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Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

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4 0
4 years ago
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