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3 years ago

11

Math help? please.......

1 answer:

saveliy_v [14]3 years ago

6 0

The answer is
$- 4 + \sqrt{11}$

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Solve for r.<br> –5 ≥ 5 (r+5)

aleksandr82 [10.1K]

Answer:

-6 ≥ r

Step-by-step explanation:

–5 ≥ 5 (r+5)

Divide each side by 5

–5/5 ≥ 5/5 (r+5)

–1 ≥ (r+5)

Subtract 5 from each side

-1-5 ≥ r+5-5

-6 ≥ r

5 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$

Simplifying by 2

$x^2-6x+10=0$

Completing squares

$x^2-6x+9+10-9=0$

Factoring and rearranging

$(x-3)^2=-1$

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0

3 years ago

Look at each situation. Is it represented by the equation -3 + 3 = 0? Determine yes or no for each. If NO, explain why not.**

lakkis [162]

Answer:

D.Jason pays $3 on the $3 he owes in fines Yes or No?

Step-by-step explanation:

6 0

2 years ago

Please help and explain how you solved it. Thanks.

galina1969 [7]

Answer:

This is 0.14 to the nearest hundredth

Step-by-step explanation:

Firstly we list the parameters;

Drive to school = 40

Take the bus = 50

Walk = 10

Sophomore = 30

Junior = 35

Senior = 35

Total number of students in sample is 100

Let W be the event that a student walked to school

So P(w) = 10/100 = 0.1

Let S be the event that a student is a senior

P(S) = 35/100 = 0.35

The probability we want to calculate can be said to be;

Probability that a student walked to school given that he is a senior

This can be represented and calculated as follows;

P( w| s) = P( w n s) / P(s)

w n s is the probability that a student walked to school and he is a senior

We need to know the number of seniors who walked to school

From the table, this is 5/100 = 0.05

So the Conditional probability is as follows;

P(W | S ) = 0.05/0.35 = 0.1429

To the nearest hundredth, that is 0.14

3 0

3 years ago

Giving brainiest explain answer

enot [183]

Answer:

A.) -5

Step-by-step explanation:

<em>Slope Formula ---> </em> $m = \frac{y_2 - y_1}{x_2 - x_1}$ <em>m = slope</em>

$m = \frac{2 - (-3)}{-2 - (-1)}$

<em>Eliminate negatives:</em>

$m = \frac{2 + 3}{ -2 + 1}$

<em>Solve:</em>

$m = \frac{5}{-1}$

<em>Simplify:</em>

$m = -5$

7 0

3 years ago