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2 years ago

A sound wave has a speed of 343 m/s in air. What is the wavelength of a sound wave with a frequency of 686 Hz

Physics

1 answer:

Svetradugi [14.3K]2 years ago

6 0

Wavelength is the distance between 2 adjacent points in a wave

we can use the following equation to find the wavelength of a sound wave

wavelength = speed / frequency

frequency is the number of waves passing a point in 1 second

substituting the values in the equation

wavelength = 343 m/s / 686 Hz

wavelength = 0.5 m

wavelength of the wave is 0.5 m

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Answer:

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Explanation:

We have given initial length of the steel guitar l = 1 m

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So stress $=\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa$

We know that young's modulus $=\frac{stress}{strain}$

So $2\times 10^{11}=\frac{3\times 10^{9}}{strain}$

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2 years ago

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A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average

alexgriva [62]

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A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 214 N/C. The electrical p

Andrei [34K]

Answer:

13.4 x 10 raise to power -19 C

Explanation:

. The distance moved by a charge in the direction of a uniform electric field is d= 1.8 cm =0.018 m

. The uniform electric field is E = 214 N/M

, The decrease in electrical potential energy is d(P.E) = 51.63 x 10 raise to power -19 J

Let the magnitude of the charge of the moving particle be q

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d(P.E) =qEd

51.63 x 10 power -19 = q(214)(0.018)

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2 years ago

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The potential difference between points a and b is zero.

<h3>Total emf of the series circuit</h3>

The total emf in the circuit is the sum of all the emf in the circuit.

emf(total) = 1.5 + 1.5 = 3.0 V

<h3>Potential difference</h3>

The potential difference between two points, a and b is calculated as follows;

V(ab) = Va - Vb

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V(ab) = 0

Thus, the potential difference between points a and b is zero.

Learn more about potential difference here: brainly.com/question/3406867

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