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3 years ago

How many hydrogen atoms are there in the following compound: 4CHA (2 points)

Physics

2 answers:

pogonyaev3 years ago

6 0

Answer:

answer a, 4

Explanation:

when the 4 is before the compound it applies to the whole compound

nadezda [96]3 years ago

5 0

4 is correct

not just because of the compound number, but because the compound is in front of all three components.

for example:

CH∧4A= 4 hydrogen and 1 of the rest

4CHA= 4 of all three components

HOPE THIS HELPS!!!:)

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Calculate the separation between the two lowest levels for an O2 molecule in a one-dimensional container of length 5.0 cm. At wh

MariettaO [177]

Answer:

The separation between the two lowest levels = $1.24 * 10^{-39}J$

The values of n where the energy of molecule reaches 1/2 kT at 300K = $2.2 * 10^{9}$

The separation at this level = 1.8 * $10^{-30}$ J

Explanation:

Knowing the formula

En = $\frac{n^{2} h^{2} }{8 mL^{2} }$

Mass of oxygen molecule

m (O2) = 32 amu * $\frac{1.6605 * 10^{-27 kg} }{1 amu}$

So the energy diference between the two lowest levels:

E2 - E1 = $\frac{3h^{2} }{8mL^{2} }$

E2 - E1 = $\frac{3 * (6.626 * 10^{-34} Js)^{2} } {8 * 32 amu * (\frac{1.6605 * 10^{-27 kg} }{1 amu})* (5*10^{-2})^{2} } = 1.24 * 10^{-39}J$

Now we should find n where the energy of molecule reaches 1/2 kT

En = $\frac{n^{2} h^{2} }{8 mL^{2} }$ = $\frac{1}{2}kT$

$\frac{h^{2} }{8 mL^{2} }$ = $4.13 * 10^{-14}J$

$n^{2} * (4.13 * 10^{-14}J) = \frac{1}{2} (1.38 * 10^{-23}JK^{-1}) * 300K$

$n = 2.2 * 10^{9}$

by the end is necessary to calculate the separation of the level

En - En-1 = $(n^{2} - (n - 1)^{2}) * \frac{h^{2} }{8 mL^{2} }$

= 1.8 * $10^{-30}$ J

4 0

3 years ago

Simple Harmonic Motion

Delvig [45]

- The net force is greatest at the position of maximum displacement

- The net force is zero when at the equilibrium position

Explanation:

The motion of a spring is a Simple Harmonic Motion, in which the displacement of the end of the spring is given by a periodic function of the form

$x=Asin (\omega t)$

where A is the amplitude (the maximum displacement), and $\omega$ the angular frequency of the motion.

We can analyze the net force acting on the spring by looking at Hooke's law:

$F=kx$

where

F is the net force

k is the spring constant

x is the displacement

From the equation, we notice immediately that:

The net force is the greatest when the displacement x is the greates, so at the position in which the spring has maximum compression or stretching
The net force is zero when the displacement x is zero, so when the spring crosses the equilibrium position

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

7 0

3 years ago

Which law of motion explains what happens during a ride on the bumper cars ?

fomenos

Answer:

Newtows first law of motion

8 0