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2 years ago

1. Use synthetic division to determine each quotient. Show your work.

Mathematics

1 answer:

Brut [27]2 years ago

5 0

A= x^2+2x-6
B= x^3-x+5-(28/x+3)

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What is the constant of vanation,<br>of the line y = for through (3.18) and (5,30)?

Naily [24]

the constant of variation or namely its slope will be

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{30}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{30-18}{5-3}\implies \cfrac{12}{2}\implies 6$

8 0

3 years ago

EGF and GFH are a linear pair, m EFG = 4n + 15, and m GFH = 5n + 39. what are m EFG and m GFH?

Tasya [4]

The angles of ∠EFG and ∠GFH are 71° and 109°

<h3>What are linear pair angles?</h3>

Linear pair of angles are formed when two lines intersect each other at a single point.

In other words, a linear pair of angles is a pair of adjacent angles formed when two lines intersect each other.

Linear pair angles are supplementary. This means the sum of a linear pair angles is 180 degrees.

Therefore,

∠EFG + ∠GFH = 180

Therefore,

∠EFG = 4n + 15

∠GFH = 5n + 39

hence,

4n + 15 + 5n + 39 = 180

9n + 54 = 180

9n = 180 - 54

9n = 126

n = 126 / 9

n = 14

Hence,

∠EFG = 4n + 15 = 4(14) + 15 = 71°

∠GFH = 5n + 39 = 5(14) + 39 = 109°

learn more on linear pair angles here: brainly.com/question/28264317

#SPJ1

4 0

1 year ago

if hannah had $20.00 and her mom took the $20.00 but she was gave ten dollars how much would she have

lions [1.4K]

Answer:

She currently has $10.00.

Step-by-step explanation:

$20.00 - $20.00 + $10.00

$00.00 + $10.00 = $10.00

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3 years ago

Read 2 more answers

Solve simultaneously <br> Y=x-2<br> Y^2=x

omeli [17]

$\left \{ {{y=x-2} \atop {\ y^2=x}} \right. \\ \\ \\
y=x-2 \\
y^2=(x-2)^2=x^2-4x+4 \\ \\ \\
y^2=x \\
x^2-4x+4=x \\
x^2-5x+4=0$

$a=1 \\ b=-5 \\ c=4 \\ \\ x=\frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 1 \cdot 4}}{2 \cdot 1}=\frac{5 \pm \sqrt{25 - 16}}{2}=\frac{5 \pm \sqrt{9}}{2}=\frac{5 \pm 3}{2} \\ \\
x=\frac{5+3}{2} \ \lor \ x=\frac{5-3}{2} \\ \\
x=\frac{8}{2} \ \lor \ x=\frac{2}{2} \\ \\
x=4 \ \lor \ x=1$

$y=4-2 \ \lor \ y=1-2 \\
y=2 \ \lor \ y=-1 \\ \\ \\
 \left \{ {{x=4} \atop {y=2}} \right. \ \lor \ \left \{ {{x=1} \atop {y=-1}} \right.$

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3 years ago

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I’m confused in the exponential

Anna [14]

Answer:

this mean in case of multiplying exponents with same base you should add the exponent and keep base same.

example:

${6}^{4} \times {6}^{5 } = {6}^{4 + 5} \\ = {6}^{9}$

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2 years ago