A wooden spoon insulates itself and retains no heat, a mental spoon would retain heat, and probably burn your hand<span />
<span>a person or thing that traces something or by which something may be traced</span>
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
Best regards!
Answer:
an exothermic reaction that Increase in entropy
Since we already have the counts of the number of moles of each element in 1 mole of ammonium nitrate (which are 2 mol N, 4 mol H, 3 mol O), we multiply each of these by the molar masses:
N has a molar mass of 14.0 g/mol, so multiplying by 2 mol N gives 28.0 g N
H has a molar mass of 1.0 g/mol, so multiplying by 4 mol H gives 4.0 g H
O has a molar mass of 16.0 g/mol, so multiplying by 3 mol O gives 48.0 g O
So there are 28.0 g N, 4.0 g H, and 48.0 g O. (The total mass would be 80.0 g ammonium nitrate.)
